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Nitella [24]
2 years ago
15

A truck delivers 478 dozen eggs to stores in one day. Write an expression that finds the number of eggs the truck delivers in on

e day.
THANK YOU!!
Mathematics
2 answers:
ki77a [65]2 years ago
6 0
U have u have to multiply 478 and 12 and if u multiply right you will get 5,736
7nadin3 [17]2 years ago
4 0
478*12= answer which the answer is: 5736
You might be interested in
A car company sells a scale model to of the size of one of its cars.
mixer [17]

Answer:

w = 13500 --- real windscreen

v = 408 --- scale volume

Step-by-step explanation:

Given

k = \frac{1}{10} --- scale factor

See attachment

Required

Complete the table

To get the windscreen (w) of the real car, we do the following computation

w = \frac{w_{scale}}{k^2}

This gives:

w = \frac{135}{(1/10)^2}

w = \frac{135}{1/100}

w = 13500

Next, the volume (v) of the scale mode

We make use of the following computation

v = v_{real} * k^3

So, we have:

v = 408000 * (1/10)^3

v = 408000 * 1/1000

v = 408

7 0
2 years ago
7.9-3.47=please show me how to rewrite it vertically?
Lemur [1.5K]

Answer:

4.43

Step-by-step explanation:

7.90

- 3.47

__________

4. 4 3

I couldn't regroup but of you cross out 0 and put 10, 10-7= 3

and you have to borrow one from 9 and make it 8 and 8-4=4

4 0
2 years ago
Find the unit price of 60lbs of honey for $123.99. Round your answer to the nearest cent if necessary.
astraxan [27]
The unit price is $2.07 per lb (pound).
6 0
2 years ago
Read 2 more answers
ana and christion collect stamps.together they have 500 stamps in their collection. ana has 150 fewer stamps then christian.how
mezya [45]
Lets represent Ana and Christion using the Letters A and C
a+c=500
c=a+150
now substitute c for a+150 back into the first equation
a+a+150=500
a+a=350
2a=350
Divide by two
a=175
Now that we know annie has 175 all we do is subtract that from the total (500)
C=325
Sure enough, 175 is 150 less than 325
Hope that helped, send me a message if you need clearing up :D
6 0
2 years ago
Report Error Suppose $P(x)$ is a polynomial of smallest possible degree such that: $\bullet$ $P(x)$ has rational coefficients $\
motikmotik

Answer:

We want a polynomial of smallest degree with rational coefficients with zeros in \sqrt{7}, 1 - \sqrt{6} and -3. The last root gives us the factor (x+3). Hence, our polynomial is

P(x) =(x+3)q(x)

where q is a polynomial with rational coefficients and roots \sqrt{7} and 1 - \sqrt{6}. The root \sqrt{7} gives us a factor x-\sqrt{7}, but in order to obtain rational coefficients we must consider the factor x^2-7.

An analogue idea works with 1 - \sqrt{6}. For convenience write  x - 1 + \sqrt{6} = ( x - 1) + \sqrt{6}. This gives the factor (x-1)^2-6. Hence,

P(x) = (x+3)(x^2-7)((x-1)^2-6)=x^5+x^4-18x^3-22x^2+77x+105

Notice that P(-1)=24. So, in order to satisfy the last condition we divide by 3 the whole polynomial, without altering its roots. Finally, the wanted polynomial is

P(x) =(1/3)x^5+(1/3)x^4-6x^3-(22/3)x^2+(77/3)x+35

Step-by-step explanation:

We must have present that any polynomial it's determined by its roots up to a constant factor. But here we have irrational ones, in order to eliminate the irrational coefficients that a factor of the type x-\sqrt7 will introduce in the expression, we need to multiply by its conjugate x+\sqrt7. Hence, we will obtain x^2-7 that have rational coefficients. Finally, the last condition is given with the intention to fix the constant factor. Usually it is enough to evaluate in the point and obtain the necessary factor.

4 0
2 years ago
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