All categories

2 years ago

Could someone help me please

Mathematics

2 answers:

Ymorist [56]2 years ago

7 0

Jupiter has greatest mass.

salantis [7]2 years ago

7 0

a) If you calculaate everything, you'll find out that Jupiter has the highest mass, not only because that is what the answer syas, because it's also an exponent of a higher number (27).

b) Mercury:

4.88 * 10^3 (diameter). Radius is the half the diameter, so:

$(4,88*10^{3}) / 2$

$(4,88*1000) / 2$

$4880 / 2$

$\bf~2440$ → radius of Mercury in km.

c) Mass of Jupiter:

$1,898 *10^{27}$ = 1898000000000000000000000000000 kg

Mass of Saturn:

$5.86*10^{26}$ = 586000000000000000000000000 kg

Difference:

1898000000000000000000000000000 - 586000000000000000000000000 = 1 897 414 000 000 000 000 000 000 000 000 kg

Hope it helped,

BioTeacher101

You might be interested in

a sheet of acrylic has a mass of 95.2g. Acrylic has a density of 1.19g/cm³ What is the volume of the sheet of acrylic

professor190 [17]

Answer:

80 cm³

Step-by-step explanation:

Density = mass/volume

1.19 = 95.2/volume

Volume = 95.2/1.19

= 80

4 0

2 years ago

Read 2 more answers

Tara owes $14,375 in credit card debt. The interest accrues at a rate of 5.3%. She is also borrowing $570 each month for rent fr

siniylev [52]

Answer:

$(f + g)(t) = f(t) + g(t) = 14375 (1 + \frac{5.3}{100})^{t} + 6840t$

$29619.13

Step-by-step explanation:

a. Tara has $14375 in credit card debt and the interest rate is 5.3%.

Now, if f(t) represent the amount of money Tara have in credit card debt, where t is the number of years after after interest begins to accrue, then

$f(t) = 14375 (1 + \frac{5.3}{100})^{t}$ ......... (1)

Again Tara borrows $570 each month for rent from her parents without any interest.

If g(x) represent the amount of money Tara owes to her parents, where t represents the number of years passed,then we can write

g(t) = 570 × 12t = 6840t ........ (2)

Therefore, $(f + g)(t) = f(t) + g(t) = 14375 (1 + \frac{5.3}{100})^{t} + 6840t$

b. So, for t = 2 years,

$(f + g)(t) = 14375 (1 + \frac{5.3}{100})^{2} + 6840 \times 2$ = $29619.13

So, Tara has to repay $29619.13 if she continues this way without any repayment for 2 years. (Answer)

7 0

1 year ago

A random sample of 35 undergraduate students who completed two years of college were asked to take a basic mathematics test. The

lisov135 [29]

Answer:

$(75.1 -72.1) -1.66 \sqrt{\frac{12.8^2}{35} +\frac{14.6^2}{50}}= -1.96$

$(75.1 -72.1) +1.66 \sqrt{\frac{12.8^2}{35} +\frac{14.6^2}{50}}= 7.96$

And the confidence interval would be given by:

$-1.96 \leq \mu_1 -\mu_2 \leq 7.96$

And since the confidence interval contains the value 0 we have enough evidence to conclude that we don't have significant differences between the two means at 10% of significance.

Step-by-step explanation:

For this case we have the following info given :

$\bar X_1= 75.1$ represent the sample mean for the scores of the undergraduate students

$s_1 = 12.8$ represent the standard deviation for the undergraduate students

$n_1 =35$ the sample size for the undergraduate

$\bar X_2= 72.1$ represent the sample mean for the scores of the high school students

$s_2 = 14.6$ represent the standard deviation for the high school students

$n_2 =50$ the sample size for the high school

The confidence interval for the true difference of means is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

The degrees of freedom are given by:

$df=n_1 +n_2 -2= 35+50-2=83$

The confidence level is 90% and the significance level is $\alpha=0.1$ and $\alpha/2 =0.05$ then the critical value would be:

$t_{\alpha/2}= 1.99$

And replacing the info we got:

$(75.1 -72.1) -1.66 \sqrt{\frac{12.8^2}{35} +\frac{14.6^2}{50}}= -1.96$

$(75.1 -72.1) +1.66 \sqrt{\frac{12.8^2}{35} +\frac{14.6^2}{50}}= 7.96$

And the confidence interval would be given by:

$-1.96 \leq \mu_1 -\mu_2 \leq 7.96$

And since the confidence interval contains the value 0 we have enough evidence to conclude that we don't have significant differences between the two means at 10% of significance.

8 0

2 years ago

A fitted multiple regression equation is Y = 28 + 5X1 - 4X2 + 7X3 + 2X4. When X1 increases 2 units and X2 increases 2 units as w

ad-work [718]

Answer:

A. Increase by 2

Step-by-step explanation:

Given that a fitted multiple regression equation is

$Y = 28 + 5X_1 -4X_2 + 7X_3 + 2X_4$

This is a multiple regression line with dependent variable y and independent variables x1, x2, x3 and x4

The coefficients of independent variables represent the slope.

In other words the coefficients represent the rate of change of y when xi is changed by 1 unit.

Given that x3 and x4 remain unchanged and x1 increases by 2 and x2 by 2 units

Since slope of x1 is 5, we find for one unit change in x1 we can have 5 units change in y

i.e. for 2 units change in x1, we expect 10 units change in Y

Similarly for 2 units change in x2, we expect -2(4) units change in Y

Put together we have

$10-8 =2$ change in y

Since positive 2, there is an increase by 2

A. Increase by 2

5 0

2 years ago

Consider the graph of Bx + Cy = A where A, B, and C are all positive constants. Find the coordinates of the x-intercept. Use upp

timofeeve [1]

That is where the line crosses the x axis or where y=0
set y=0
Bx=A
find x value
divie both sides by B
x=A/B
the x intercept is x=A/B

3 0

2 years ago

Read 2 more answers