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Vedmedyk [2.9K]
2 years ago
6

The math team wraps gifts as a way to raise money for traveling to competitions. They offer two choices: a plain wrapping or a d

ecorative wrapping with bows. The table represents the money raised over a busy shopping weekend.
Which statement describes the amounts the team charged for wrapping gifts?
Mathematics
2 answers:
VladimirAG [237]2 years ago
5 0
The information of the table permits you to state these equations:

10x + 9 y = 47

25x + 12 y = 86

16x + 12 y = 68


By subtracting the third equation from the first, you get:

9x = 18

=> x = 18 / 9 = 2


Now using any of the equations you can obtain the value of y.

I will use the first equation:

10x + 9y = 47 => 9y = 47 - 10 (2)  = 27

=> y = 27 / 3 = 3


Those results are interpreted as they charge $2 for each plain wrapping and $3 for each decorative wrapping.


Then, the correct choice is " the team charged $2 to wrap a gift with no bow and $3 to wrap a gift with no bow"
Mrrafil [7]2 years ago
5 0

Answer:

The team charged $2 to wrap a gift with no bow and $3 to wrap a gift with a bow. ( B.)

Step-by-step explanation:

I hope I help you.

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The coordinates of the vertices for the figure HIJK are H(0, 5), I(3, 3), J(4, –1), and K(1, 1).
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Answer: The quadrilateral HIJK is a parallelogram.

Explanation:

It is given that the coordinates of the vertices for the figure HIJK are H(0, 5), I(3, 3), J(4, –1), and K(1, 1).

The parallelogram diagonal theorem states that  the quadrilateral is a parallelogram if both diagonal bisects each other.

If HIJK is a quadrilateral, then HJ and IK are the diagonals of HIJK.

First we find the midpoint of HJ.

\text{Midpoint of HJ}=(\frac{0+4}{2}, \frac{5-1}{2})

\text{Midpoint of HJ}=(2,2)

Now, find the midpoint of IK.

\text{Midpoint of IK}=(\frac{3+1}{2}, \frac{3+1}{2})

\text{Midpoint of IK}=(2,2)

The midpoint of both diagonal are same. It means the diagonals of HIJK bisects each other.

By parallelogram diagonal theorem, we can say that the quadrilateral HIJK is a parallelogram.

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A number, x, rounded to 2 significant figures is 1300<br>Write down the error interval for x.​
nikitadnepr [17]

Answer:

[1250,1350).

Step-by-step explanation:

It is given that a number, x, rounded to 2 significant figures is 1300.

It is possible if,

1. The value of x is greater than of equal to 1250 and less than or equal to 1300.

i.e., 1250\leq x\leq 1300     ...(1)

2. The value of x is greater than of equal to 1300 and less than 1350.

i.e., 1300\leq x       ...(2)

On combining (1) and (2), we get

1250\leq x < 1350

1350 is not included in the error interval for x.​

Interval notation is [1250,1350).

Therefore, the error interval for x is [1250,1350).

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There are 345 students at a college who have taken a course in calculus, 212 who have taken a course in discrete mathematics, an
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Answer:

369 students have taken a course in either calculus or discrete mathematics

Step-by-step explanation:

I am going to build the Venn's diagram of these values.

I am going to say that:

A is the number of students who have taken a course in calculus.

B is the number of students who have taken a course in discrete mathematics.

We have that:

A = a + (A \cap B)

In which a is the number of students who have taken a course in calculus but not in discrete mathematics and A \cap B is the number of students who have taken a course in both calculus and discrete mathematics.

By the same logic, we have that:

B = b + (A \cap B)

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212 who have taken a course in discrete mathematics

This means that B = 212

345 students at a college who have taken a course in calculus

This means that A = 345

How many students have taken a course in either calculus or discrete mathematics

(A \cup B) = A + B - (A \cap B) = 345 + 212 - 188 = 369

369 students have taken a course in either calculus or discrete mathematics

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