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2 years ago

Which binomial is a factor of x4 − 4x2 − 4x 8?

Mathematics

1 answer:

Anastasy [175]2 years ago

6 0

The given polynomial is

$x^4-4x^2-4x-8$

As this is a fourth degree polynomial, we can not directly use any formula, So here we will use hit and trial method

check whether x=-1 is a zero of the polynomial or not

$(-1)^4-4(-1)^2-4(-1)-8=-7$

Hence x=-1 is not a zero.

Now check whether x=-2 is a zero of the polynomial or not

$(-2)^4-4(-2)^2-4(-2)-8=0$

Hence x=-2 is a zero of the polynomial.

Hence we can re-write the polynomial as

$x^4-4x^2-4x-8=x^4+2x^3-2x^3-4x^2-4x-8\\ \\ =x^3(x+2)-2x^2(x+2)-4(x+2)\\ \\ =(x+2)(x^3-2x^2-4)\\$

Hence the required binomial is (x+2)

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When 54,702 is divided by 25, the quotient is 2,188 R ___.

iogann1982 [59]

Hello There!

The quotient is 2'188 R 2

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calculeaza lungimea segmentului ab in fiecare dintre cazuri:A(1,5);B(4,5);A(2,-5),B(2,7);A(3,1)B(-1,4);A(-2,-5)B(3,7);A(5,4);B(-

Tatiana [17]

Answer:

1. 3; 2. 12; 3. 5; 4. 13; 5. 10; 6. 10

Step-by-step explanation:

We can use the distance formula to calculate the lengths of the line segments.

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}$

1. A (1,5), B (4,5) (red)

$d = \sqrt{(x_{2} - x_{1}^{2}) + (y_{2} - y_{1})^{2}} = \sqrt{(4 - 1)^{2} + (5 - 5)^{2}}\\= \sqrt{3^{2} + 0^{2}} = \sqrt{9 + 0} = \sqrt{9} = \mathbf{3}$

2. A (2,-5), B (2,7) (blue)

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(2 - 2)^{2} + (7 - (-5))^{2}}\\= \sqrt{0^{2} + 12^{2}} = \sqrt{0 + 144} = \sqrt{144} = \mathbf{12}$

3. A (3,1), B (-1,4 ) (green)

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-1 - 3)^{2} + (4 - 1)^{2}}\\= \sqrt{(-4)^{2} + 3^{2}} = \sqrt{16 + 9} = \sqrt{25} = \mathbf{5}$

4. A (-2,-5), B (3,7) (orange)

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(3 - (-2))^{2} + (7 - (-5))^{2}}\\= \sqrt{5^{2} + 12^{2}} = \sqrt{25 + 144} = \sqrt{169} = \mathbf{13}$

5. A (5,4), B (-3,-2) (purple)

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-3 - 5)^{2} + (-2 - 4)^{2}}\\= \sqrt{(-8)^{2} + (-6)^{2}} = \sqrt{64 + 36} = \sqrt{100} = \mathbf{10}$

6. A (1,-8), B (-5,0) (black)

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-5 - 1)^{2} + (0 - (-8))^{2}}\\-= \sqrt{(-6)^{2} + (-8)^{2}} = \sqrt{36 + 64} = \sqrt{100} = \mathbf{10}$

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1 year ago

A contractor has at most $42 to spend on nails for a project. Finishing nails cost $0.45 per pound and common nails cost $0.60 p

mojhsa [17]

Question:

A contractor has at most $42 to spend on nails for a project. Finishing nails cost $0.45 per pound and common nails cost $0.60 per pound. He would like to purchase at least 30 pounds of nails total. Write a system of linear inequalities

Answer:

The system of linear inequalities are:

$x + y\geq 30\\\\0.45x+0.60y\leq 42$

Solution:

Let "x" be the pounds of finishing nails

Let "y" be the pounds of common nails

Given that,

He would like to purchase at least 30 pounds of nails total.

"at least" means that he can purchase 30 pounds or more than 30 pounds also

So, we have to use "greater than or equal to" symbol

$x + y\geq 30$

From given,

Cost of 1 pound of finishing nail = $ 0.45

Cost of 1 pound of common nail = $ 0.60

A contractor has at most $42 to spend on nails for a project

"at most" means he can spend 42 or less than 42

So we have to use " less than or equal to" symbol

Thus we frame a inequality as:

$x \times 0.45 + y \times 0.60\leq 42\\\\0.45x + 0.60y\leq 42$

Thus the system of inequalities are:

$x + y\geq 30\\\\0.45x+0.60y\leq 42$

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1 year ago

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stich3 [128]

Answer:

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Step-by-step explanation:

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