Answer:
The total cost function of having a party catered is f(p) = 65 + 9.50 p
Step-by-step explanation:
The equipment fee of the caterer = $65
The charge per plate = $9.50
Let, Total number of people invited in the party = p
So, the cost of plates of p people = Number of people x Per plate cost
= p x $9.50
Now, Total Catering Cost = Equipment Fee + Cost of all plates
or, Total cost = $65 + p x $9.50
Hence, the total cost function of having a party catered
is f(p) = 65 + 9.50 p.
F(x) = [x] - 2 + 8
[x] is the notation for 'greatest integer function'
f(-1.8) = [-1.8] - 2 + 8 = -2 -2 + 8 = 4
The answer is 4
Answer:
Step-by-step explanation:
Let 
represent the cost of the torch and 
represent the cost of the battery.
The torch and a battery cost £2.50 altogether.
The torch costs £2.00 more than the battery.
We substitute the second equation into the first equation to get;
£2.50
The price of the battery is £0.25
We express this as a fraction of the total cost which is £2.50 to get;
Answer:
Revenue = 5( 1000 + w+ k)
Step-by-step explanation:
Lets calculate expenses first
rent = $1000
wages = w
overhead cost = k
Total cost = rent + wage+ overhead
Total cost = 1000 + w+ k
Given Jose wants his monthly sales revenue, x, to be 4 times greater than the operating costs
Let revenue be R
Thus, putting the statement mathematically
revenue - total cost = 4 * operating cost
R - ( 1000 + w+ k) = 4( 1000 + w+ k)
R = 4( 1000 + w+ k) + ( 1000 + w+ k)
R = 5( 1000 + w+ k)
Thus, revenue should be 5( 1000 + w+ k).
Answer:
a. ∫ xSinx dx
iii. integration by parts
u =x and dv= sinx
b. ∫ x⁴/(1+x³). dx
ii. neither
Long division is an option here before integration is done
c. ∫ x⁴. e^x³. dx
i. substitution
where u = x⁵
d. ∫x⁴ cos(x⁵). dx
i. substitution
where u = x⁵
e. ∫1/√9x+1 .dx
i. substitution
where u = 9x+1
