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nataly862011 [7]
2 years ago
8

Martin puts two bowls of fruit out for his friends.The bowl of grapes has 9 green grapes and 16 red grapes. The bowl of tangerin

es has 7 seeded and 3 seedless tangerines.
Martin's friend chooses a random grape and a random tangerine. What is the probability that she chooses a green grape and a seedless tangerine?
Mathematics
2 answers:
Anarel [89]2 years ago
8 0

Answer:

27/250

Step-by-step explanation:

P(a green grape and a seedless tangerine)

=P(green grape) x P(seedless tangerine)

The bowl of grapes has 9 green grapes and 16 red grapes.

P(green grape)=green grapes / total grapes

=9/(9+16)

=9/25

The bowl of tangerines has 7 seeded and 3 seedless tangerines.

P(seedless tangerine)=seedless / total

=3/(3+7)

=3/10

P(a green grape and a seedless tangerine)

=9/25 x 3/10

=27/250

ArbitrLikvidat [17]2 years ago
3 0

Answer:

Step-by-step explanation:

There are two requirements: a green grape and a seedless tangerine

For grapes, total number of grapes is 9+16 = 25 and 9 are green

Prob (green grape)=9/25

For tangerines, total number of tangerines is 7+3 = 10 and 3 are seedless

Prob (seedless tangerine)=3/10

Prob (a green grape and a seedless tangerine)=9/25*3/10

=27/250

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Answer:

5% I think

Step-by-step explanation:

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2 years ago
The lifetime of a cheap light bulb is an exponential random variable with mean 36 hours. Suppose that 16 light bulbs are tested
photoshop1234 [79]

Answer:

P(T

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent "The number of years a radio functions" and we know that the distribution is given by:

X \sim Exp(\lambda=\frac{1}{16})

Or equivalently:

X \sim Exp(\mu=16)

Solution to the problem

For this case we are interested in the total T, and we can find the mean and deviation for this like this:

\bar X =\frac{\sum_{i=1}^n X_i}{n}=\frac{T}{n}

If we solve for T we got:

T= n\bar X

And the expected value is given by:

E(T) = n E(\bar X)= n \mu= 16*36=576

And we can find the variance like this:

Var(T) = Var(n\bar X)=n^2 Var(\bar X)= n^2 *\frac{\sigma^2}{n}=n \sigma^2

And then the deviation is given by:

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And the distribution for the total is:

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And we want to find this probability:

P(T< 600)

And we can use the z score formula given by:

z=\frac{T- \mu_T}{\sigma_T}

And replacing we got this:

P(T

6 0
2 years ago
Kaitlyn gave 1/2 of her candy bar to arianna. arianna gave 1/3 of the candy she got from kaitlyn to cameron. what fraction of a
sukhopar [10]
Let the total candy bar be represented by x.

Amount of chocolate Kaitlyn gave to Arianna = \frac{1}{2}x

Amount of chocolate Arianna gave Cameron 

= \frac{1}{3} rd <span>of the candy she got from Kaitlyn to Cameron

= </span>\frac{1}{3} × \frac{1}{2}x

= \frac{1}{3}* \frac{1}{2} x  =  \frac{1}{6} x

Hence, Cameron got \frac{1}{6} th of the original chocolate.
5 0
2 years ago
According to a Wired magazine article, of e-mails that are received are tracked using software that can tell the e-mail sender w
VladimirAG [237]

Answer:

a. 12

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Step-by-step explanation:

The computation is shown below:

Given that

P = 0.40 and n = 30

a)

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b)

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Now

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= 2.683

We simply applied the above formula

8 0
1 year ago
X<br><img src="https://tex.z-dn.net/?f=x%200.8265%20%3D%2045%20" id="TexFormula1" title="x 0.8265 = 45 " alt="x 0.8265 = 45 " al
Sonbull [250]

0.8265x = 45 \\ x = 45  \div 0.8265  \\ x = 45 \times  \frac{10000}{8265}  \\ x =  \frac{45000}{8265}  \\ x = 54 \frac{3690}{8265}  \\ x = 54 \frac{246}{551}

3 0
2 years ago
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