Answer:
1) 2/7
2) 8/11
3) 3/2 or 1 1/2
4) 32/35
Step-by-step explanation:
1.5/7•14/35
= 5/7 × 14/35
Using Cancellation method
= 1/1 × 2/7
= 2/7
2.[4/5][10/11]
= 4/5 × 10/11
Using Cancellation method
= 4/1 × 2/11
= 8/11
3.8 3/4 multiplied by 2/9
= 8 3/4 × 2/9
= 27/4 × 2/9
= 3/2 × 1/1
= 3/2
= 1 1/2
4. [4/5]10/11][7/8]
40/50 ÷ 77/88
= 40/50 × 88/77
= 40/50 × 8/7
= 40/25 × 4/7
= 8/5 × 4/7
= 32/35
This is late, but for anyone searching the answer up in the future, the answer on Edg.enuity is the last one - where the graph starts out as a horizontal line, then decreases and touches the x-axis, then increases again.
Good luck on your assignment !!
Answer:
C, they are the same
Step-by-step explanation:
I got it right on Khan Academy! Please mark me as brainliest. Stay safe y'all. Btw, I'm not lying, it is correct. <3
Answer:
Step-by-step explanation:
Consider the given matrix
![A=\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-2%263%5C%5C2%2617%260%5C%5C3%2622%268%5Cend%7Barray%7D%5Cright%5D)
Let matrix B is
![B=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db_%7B11%7D%26b_%7B12%7D%26b_%7B13%7D%5C%5Cb_%7B21%7D%26b_%7B22%7D%26b_%7B23%7D%5C%5Cb_%7B31%7D%26b_%7B32%7D%26b_%7B33%7D%5Cend%7Barray%7D%5Cright%5D)
It is given that
![\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-2%263%5C%5C2%2617%260%5C%5C3%2622%268%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db_%7B11%7D%26b_%7B12%7D%26b_%7B13%7D%5C%5Cb_%7B21%7D%26b_%7B22%7D%26b_%7B23%7D%5C%5Cb_%7B31%7D%26b_%7B32%7D%26b_%7B33%7D%5Cend%7Barray%7D%5Cright%5D)
On comparing corresponding elements of both matrices, we get
Therefore, the required values are .
See the attached picture.
<span>you are given that ABCE is an isosceles trapezoid. </span>
<span>you are given that AB is parallel to EC. </span>
<span>this means that AE is congruent to BC. </span>
<span>you are given that AE and AD are congruent. </span>
<span>triangle EAD is an isosceles triangle because AE and AD are congruent. </span>
<span>this means that angle 1 is equal to angle 3. </span>
<span>since angle 1 is equal to angle 2 and angle 3 is equal to angle 1, then angle 3 is also equal to angle 2. </span>
<span>this means that AD and BC are parellel because their corresponding angles (angles 3 and 2) are equal. </span>
<span>since AB is parallel to EC and DC is part of the same line, than AB is parallel to DC. </span>
<span>you have AB parallel to DC and AD parallel to BC. </span>
<span>if opposite sides of a quadrilateral are parallel, then the quadrilateral is a parallelogram. </span>
<span>that might be able to do it,depending on whether all these statements are acceptable without proof. </span>
<span>they are either postulates or theorems that have been previously proven. </span>
<span>if not, then you need to go a little deeper and prove some of the statements that you used.. </span>
here's my diagram.
<span>this is not a formal proof, but should give you some ideas about how to proceed. </span>
<span>you can also prove that angle 4 is equal to angle 2 because they are alternate interior angles of parallel lines. </span>
<span>you can also prove that angle 6 is equal to angle 5 because they are alternate interior angles of parallel lines. </span>
