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agasfer [191]
2 years ago
12

Rashid solved a fraction division problem using the rule “multiply by the reciprocal.” His work is shown below. Three-fourths di

vided by 9. Three-fourths times StartFraction 1 Over 9 EndFraction = StartFraction 3 Over 36 EndFraction or StartFraction 1 Over 12 EndFraction Which is the most accurate description of Rashid’s work? Rashid solved the problem correctly. Rashid multiplied the dividend by the divisor instead of finding the reciprocal. Rashid multiplied the denominators instead of finding a common denominator. Rashid multiplied with the reciprocal of the dividend instead of the reciprocal of the divisor.
Mathematics
2 answers:
pychu [463]2 years ago
5 0

Answer:

its b

Step-by-step explanation:

slega [8]2 years ago
4 0

Answer:

its B

Step-by-step explanation:

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300 reduced by twice a number is 146. what is the number?
Bogdan [553]

300 - 2x = 146, where x is the number

Subtract 300 from both sides.

-2x = -154

Divide both sides by -2.

x = 77

4 0
2 years ago
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Which rational number represents a decrease in water level from 8 feet to 6 feet???
cestrela7 [59]

Answer:

C) -2

Step-by-step explanation:

8 + (-2) = 6

6 0
2 years ago
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The average time taken to complete an exam, X, follows a normal probability distribution with mean = 60 minutes and standard dev
k0ka [10]

Answer: b. 0.8413

Step-by-step explanation:

Given : The average time taken to complete an exam, X, follows a normal probability distribution with \mu=60\text{ minutes} and \sigma=30\text{ minutes} .

Then, the  probability that a randomly chosen student will take more than 30 minutes to complete the exam will be :-

P(x>30)=P(z>\dfrac{30-60}{30})\ \ [\because\ z=\dfrac{x-\mu}{\sigma} ]\\\\=P(z>-1)=P(z-z)=P(Z

 [using z-value table]

Hence, the probability that a randomly chosen student will take more than 30 minutes to complete the exam =  0.8413

3 0
2 years ago
PLEASE HELP!!!!!!
jek_recluse [69]
\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}\\\\
-----------------------------\\\\

\begin{cases}
a=12\\
b=10\\
D=90+50
\end{cases}\implies d = \sqrt{{{ 12}}^2+{{ 10}}^2-2(12)(10)cos(140^o)}
\\\\\\
d\approx \sqrt{427.851}\implies d\approx 20.684551
5 0
2 years ago
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An airline, believing that 5% of passengers fail to show for flights, overbooks (sells more tickets than there are seats). Suppo
Fittoniya [83]

Answer:

Q1. 13 passengers

Q2. 0.1756 (approx. 0.18)

Step-by-step explanation:

Q1. 267 seats are available on the plane

5% is expected to fail to show up

Hence, no of passengers expected not to show up = 267 * 0.05

= 13.35 (approx 13 passengers)

Q2. See working in the attachment as I had to explain it step by step.

6 0
2 years ago
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