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olya-2409 [2.1K]
1 year ago
9

Choose the function whose graph is given by:

Mathematics
1 answer:
loris [4]1 year ago
5 0
<h2>Answer:</h2>

y=3sec\left(\frac{1}{2}x\right)

<h2>Step-by-step explanation:</h2>

The graphs of sec(x) can be obtained from  the graph of the cosine function using the reciprocal identity, so:

sec(x)=\frac{1}{cos(x)}

But in this problem, the graph stands for the function:

y=3sec\left(\frac{1}{2}x\right)

Because the period is now 4π as indicated and for x=0 in the figure and this can be proven as follows:

Period=\frac{2\pi}{\frac{1}{2}}=4\pi

Also, for \ x=1 \ then \ y=3 as indicated in the figure and this can be proven as:

y=3sec\left(\frac{1}{2}x\right) \\ \\ y=\frac{3}{cos(0.5x)} \\ \\ y=\frac{3}{cos(0.5(0))} \\ \\ y=\frac{3}{1}=3

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An airline, believing that 5% of passengers fail to show for flights, overbooks (sells more tickets than there are seats). Suppo
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Answer:

Q1. 13 passengers

Q2. 0.1756 (approx. 0.18)

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Q1. 267 seats are available on the plane

5% is expected to fail to show up

Hence, no of passengers expected not to show up = 267 * 0.05

= 13.35 (approx 13 passengers)

Q2. See working in the attachment as I had to explain it step by step.

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Another payment type enabled by smartphones is person-to-person payments, which are apps that allow people to send money electro
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Approximately how much principal would need to be placed into an account earning 3.575% interest compounded quarterly so that it
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<u>Answer-</u>

<em>$23377</em><em> must be deposited to get $68000 at the end of 30 years.</em>

<u>Solution-</u>

We know that for compound interest,

A=P(1+\dfrac{r}{n})^{nt}

Where,

A = Future amount = $68,000

P = ??

r = 3.575% annual = 0.03575

n = 4 as interest is compounded quarterly

t = time in year = 30 years

Putting the values,

\Rightarrow 68000=P(1+\dfrac{0.03575}{4})^{4\times 30}

\Rightarrow 68000=P(1.0089375)^{120}

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Therefore, $23377 must be deposited to get $68000 at the end of 30 years.



7 0
1 year ago
Read 2 more answers
A high school wants to sell postage stamps with the school logo on them. The fundraising group have purchased 500 sheets of stam
erma4kov [3.2K]

Answer:

a) Cost

C(q) = 50+16q\\\\C(500)=50+16(500)=50+8,000=8,050

b) Sales income

S(q)=20q\\\\S(500)=20\cdot 500 = 10,000

c) Table of values

\left[\begin{array}{ccc}q&C(q)&S(q)\\0&50&0\\250&4,050&5,000\\500&8,050&10,000\end{array}\right]

d) Attached

e) Breakeven point = 12.5 sheets

f) Profit at 550 sheets = $1,950

Step-by-step explanation:

a) We have a fixed cost for the image, at $50.

We also have a variable cost of $16 a sheet.

The purchased quantity is 500 sheets.

Then, the cost function is:

C(q) = 50+16q\\\\C(500)=50+16(500)=50+8,000=8,050

b) The price for each sheet is $20, so the income from sales are:

S(q)=20q\\\\S(500)=20\cdot 500 = 10,000

c) Table of values

\left[\begin{array}{ccc}q&C(q)&S(q)\\0&50&0\\250&4,050&5,000\\500&8,050&10,000\end{array}\right]

d) Attached

e) The minimum number of sheets the group must sell so they don't lose any money is the breakeven point (BEP) and can be calculated making the income sales equal to the cost:

S(q)=C(q)\\\\20q=50+16q\\\\(20-16)q=50\\\\4q=50\\\\q=50/4=12.5

f) This profit can be calculated as the difference between the sales income and the cost:

P(500)=S(500)-C(500)\\\\P(500)=20\cdot 500-(50+16\cdot 500)=10,000-8,050=1,950

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