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il63 [147K]
2 years ago
5

Bob paid $5.60 for 0.8 lb of fresh peaches. How much would 3.25 lb of peaches cost?

Mathematics
2 answers:
Mandarinka [93]2 years ago
5 0

Answer:

22.75

Step-by-step explanation:

5.6 divided by 0.8=Constant Variation=7

3.25*7=22.75

Rasek [7]2 years ago
3 0

Answer:

$18.20

Step-by-step explanation:

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Paco's cell phone carrier charges him $0.20 for each text message he sends or receives, $0.15 per minute for calls, and a $15 mo
Katarina [22]

Given:

Paco's cell phone carrier charges him $0.20 for each text message he sends or receives, $0.15 per minute for calls, and a $15 monthly service fee. Paco is trying to keep his bill for the month below $30.

To Find:

The number of texts 't' Paco can send/receive in a month.

Answer:

0\leq t

best describes the number of texts he can send or receive to keep his bill less than $30 in a month.

Step-by-step explanation:

Paco wants to keep is monthly bill below $30.

We see that he has to pay a foxed monthly service fee of $15. This means he is only left with a limit of $30 - $15 = $15 for his monthly calls and texts.

That is, the amount he has to pay for texting and calling has to be less than $15.

For texts, the cell phone carrier charges $0.20 for sending/receiving texts.

For calls, he is charged $0.15 per minute.

Let the number of text messages Paco can send or receive in a month be denoted by 't'.

Let the number of minutes Paco can call in a month be denoted by 'c'.

Then, the total cost of text messages he can send or receive per month would be 0.20t and the total cost of the minutes he spends on calls would be 0.15c. Together, the sum of these has to be less than $15 if his monthly bill has to be kept less than $30 (accounting for the monthly service fee).

So,

0.20t+0.15c

The number of texts he can send will dpend on the number of minutes he spends on his calls. For Paco to spend maximum number of texts, he has to spend 0 minutes on calls.

So, putting c = 0, the aboce equation can be written as

0.20t+0

That is, Paco has to send and receive less than 75 texts.

So,

0\leq t

best describes the number of texts he can send or receive to keep his bill less than $30 in a month.

3 0
2 years ago
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A multiple choice question has 18 possible​ answers, only one of which is correct. Is it​ "significant" to answer a question cor
yan [13]

Answer:

It is not ''significant''

Step-by-step explanation:

Let's call the event

A : ''Answer a question correctly if a random guess is made''

Now we calculate the probability for the event A

P(A)=\frac{cases where A occurs}{total cases}

In the exercise A occurs in only one way and the total cases are the number of possible answers

Total cases = 18

P(A)=\frac{1}{18} =0.0555555

An event B is ''significant'' if P(B)\leq 0.05

P(A)=0.0555555

⇒A it is not a ''significant'' event

8 0
2 years ago
A manufacturing company plans to progressively increase its production capacity over the next few quarters. (A quarter is a peri
SashulF [63]
We are asked in the problem to determine the number of quarters that are needed to complete 4975 units given the equation y = x6 − 25x4 + 199x2 where y is the number of manufactured units and x is the number of quarters needed. 
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5 0
2 years ago
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You and a classmate have a bug collection for science class. You find 5 out of every 9 bugs in the collection. You find 4 more bug
FrozenT [24]

Answer:

The total number of bugs in the collection is 36

Step-by-step explanation:

Let

x -----> the number of bugs that you find out

y ----> the number of bugs that the classmate find out

we know that

\frac{x}{y+x} =\frac{5}{9}  -----> equation A

x=y+4 ----> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

The solution is the point (20,16)

The total number of bugs in the collection is

(20+16)=36\ bugs

5 0
2 years ago
How do I write log7t as a base 2 logarithm?
irina [24]

Given:

The value is \log_7t.

To find:

The value as a base 2 logarithm.

Solution:

We know that,

\log_xy=\dfrac{\log_ay}{\log_ax}

where, a is any positive value.

We have,

\log_7t

Using the above property of logarithm, we get

\log_7t=\dfrac{\log_at}{\log_a7}

For a=2,

\log_7t=\dfrac{\log_2t}{\log_27}

Therefore, the given value as a base 2 logarithm can be written as \dfrac{\log_2t}{\log_27}.

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1 year ago
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