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krek1111 [17]
2 years ago
5

A rectangular porch is 4 feet wide it is 3 times as long as it is wide what is the area of the porch

Mathematics
2 answers:
nignag [31]2 years ago
6 0
So 4+4+12+12=32
Hope this helps :)
Ludmilka [50]2 years ago
3 0
3x4=12
I hope that is what you were asking for
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Schadek Silkscreen Printing Inc. purchases plastic cups and imprints them with logos for sporting events, proms, birthdays, and
Ivahew [28]

Answer:

(a) The estimated proportion of defective in the population is 0.05.

(b) The 95% confidence interval for the proportion defective cups is (2.5%, 7.5%).

(c) Zack does not needs to return the lots.

Step-by-step explanation:

Let <em>X</em> = number of defective cups.

The random sample of cups selected is of size, <em>n</em> = 300.

The number of defective cps in the sample is, <em>X</em> = 15.

(a)

The proportion of the defective cups in the population can be estimated by the sample proportion because the sample selected is quite large.

The sample proportion of defective cups is:

\hat p=\frac{X}{n}=\frac{15}{300}=0.05

Thus, the estimated proportion of defective in the population is 0.05.

(b)

The (1 - <em>α</em>)% confidence interval for population proportion is:

CI=\hat p \pm z_{\alpha/2}\times\sqrt{\frac{\hat p(1-\hat p)}{n}}

Compute the critical value of <em>z</em> for 95% confidence level as follows:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the 95% confidence interval for <em>p</em> as follows:

CI=\hat p \pm z_{\alpha/2}\times\sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.05 \pm 1.96\times\sqrt{\frac{0.05(1-0.05)}{300}}

     =0.05\pm 0.025\\=(0.025, 0.075)\\

Thus, the 95% confidence interval for the proportion defective cups is (2.5%, 7.5%).

(c)

It is provided that Zack has an agreement with his supplier that he is to return lots that are 10% or more defective.

The 95% confidence interval for the proportion defective is (2.5%, 7.5%). This implies that 95% of the lots have 2.5% to 7.5% defective items.

Thus, Zack does not needs to return the lots.

5 0
2 years ago
Alice and Bob each have a certain amount of money. If Alice receives $n$ dollars from Bob, then she will have $4$ times as much
oksano4ka [1.4K]

Answer: 31 : 9

Step-by-step explanation:

Assume the following:

Alice's amount = P

Bob's amount = Q

Amount received = n

If Alice receives $n$ dollars from Bob ;then she will have $4$ times as much money as Bob.

P + n = 4(Q - n)

P + n = 4Q - 4n

P = 4Q - 4n - n

P = 4Q - 5n - - - - (1)

If, on the other hand, she gives $n$ dollars to Bob, then she will have $3$ times as much money as Bob

P - n = 3(Q + n)

P - n = 3Q + 3n

P = 3Q + 3n + n

P = 3Q + 4n - - - - - - (2)

Equating both equations - (1) and (2)

4Q - 5n = 3Q + 4n

4Q - 3Q = 4n + 5n

Q = 9n

Express P in terms of n, use either equation (1) or (2)

From equation 2:

P = 3Q + 4n

Substituting Q = 9n

P = 3(9n) + 4n

P = 27n + 4n

P = 31n

Alice's amount = P, Bob's = Q

Ratio = P:Q

31 : 9

5 0
2 years ago
stilt scored 5 points less than twice the number scored by dunk. together they scored 43 points. how many points were scored by
gizmo_the_mogwai [7]
Set up a system of equations:

s = 2d - 5
s + d = 43

Where 's' represents the number of points Stilt scored and 'd' represents the number of points Dunk scored.

Plug in 2d - 5 for 's' in the 2nd equation:

s + d = 43

2d - 5 + d = 43

Combine like terms:

3d - 5 = 43

Add 5 to both sides:

3d = 48

Divide 3 to both sides:

d = 16

Plug this back into any of the two equations to find 's':

s + d = 43

s + 16 = 43

Subtract 16 to both sides:

s = 27

So Dunk scored 16 points and Stilt scored 27 points.
4 0
2 years ago
Cassie has 20 bracelets. How many can she give to her sister if she wants to keep 11 or more bracelets? What repeats in the poss
Mademuasel [1]
If Cassie has 20 and wants to keep 11 then we would subtract 11 from 20.

So 20 - 11 is 9.

Her sister will get 9 bracelets.

Hope this helps!
3 0
2 years ago
bob is having a party and want to order some cake. there will be 57 guest and he wants to make sure that everyone gets a slice o
Leviafan [203]
<span>Bob should by the 25cm cake for 18.75 each. He will need to buy 3 of these cakes in order to feed 57 guests. The total cost would be 56.25. If he were to buy the 20cm cake, he would need to purchase 5 cakes for a total of 67.50.</span>
4 0
2 years ago
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