A machine pumps 4 1/2 gallons of water every hour. How many gallons of water does it pump after 2 2/3

During a snowstorm, Alang tracked the amount of snow on the ground. When the storm began, there was no snow on the ground. For t

Pachacha [2.7K]

Answer:

over specific intervals. TO GRAPH PIECEWISE FUNCTIONS: 1. Create a ... function. 2. Plot correct points (if more are plotted than are required points are ... EX 6: During a snowstorm, a meteorologist tracks the amount of accumulating ... the first three hours of the storm, the snow fell at a constant rate of one inch per hour.

Step-by-step explanation:

4 0

2 years ago

• A researcher claims that less than 40% of U.S. cell phone owners use their phone for most of their online browsing. In a rando

antiseptic1488 [7]

Answer:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p > α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

Step-by-step explanation:

Set up hypotheses:

Null hypotheses = H₀: p = 0.40

Alternate hypotheses = H₁: p < 0.40

Determine the level of significance and Z-score:

Given level of significance = 1% = 0.01

Since it is a lower tailed test,

Z-score = -2.33 (lower tailed)

Determine type of test:

Since the alternate hypothesis states that less than 40% of U.S. cell phone owners use their phone for most of their online browsing, therefore we will use a lower tailed test.

Select the test statistic:

Since the sample size is quite large (n > 30) therefore, we will use Z-distribution.

Set up decision rule:

Since it is a lower tailed test, using a Z statistic at a significance level of 1%

We Reject H₀ if Z < -1.645

We Reject H₀ if p ≤ α

Compute the test statistic:

$Z = \frac{\hat{p} - p}{ \sqrt{\frac{p(1-p)}{n} }}$

$Z = \frac{0.31 - 0.40}{ \sqrt{\frac{0.40(1-0.40)}{100} }}$

$Z = \frac{- 0.09}{ 0.048989 }$

$Z = - 1.84$

From the z-table, the p-value corresponding to the test statistic -1.84 is

p = 0.03288

Conclusion:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p > α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

8 0

2 years ago

Which properties are used to add these complex numbers? Choose all that apply.

mario62 [17]

B. Associative Property , you're working out the numbers in the parentheses before anything else.

5 0

2 years ago

Read 2 more answers

A steel pipe 100 cm long has an outside diameter of 2 cm and an inside diameter of 1.8 cm. If thee density of the steel is 7.8 g

ELEN [110]

Answer:

The mass of the pipe is $465\ g$