No, Leo's answer is not a product of prime polynomials because x2 – 1 can be factored. This is a difference of squares. He should continue factoring to get
(x – 1)(x + 1)(3x + 5).
Answer:
0.2611
Step-by-step explanation:
Given the following information :
Normal distribution:
Mean (m) length of time per call = 3.5 minutes
Standard deviation (sd) = 0.7 minutes
Probability that length of calls last between 3.5 and 4.0 minutes :
P(3.5 < x < 4):
Find z- score of 3.5:
z = (x - m) / sd
x = 3.5
z = (3.5 - 3.5) / 0.7 = 0
x = 4
z = (4.0 - 3.5) / 0.7 = 0.5 / 0.7 = 0.71
P(3.5 < x < 4) = P( 0 < z < 0.714)
From the z - distribution table :
0 = 0.500
0.71 = very close to 0.7611
(0.7611 - 0.5000) = 0.2611
P(3.5 < x < 4) = P( 0 < z < 0.714) = 0.2611
Answer:
Option c (Upper tailed) is the correct choice.
Step-by-step explanation:
Given that:
The average attendance is:
= 74,900
We will have to test:
⇒ 
or,

Verses,
⇒ 
or,

The other given alternatives aren't connected to the given scenario. So the above is the correct one.
Consider this option:
C³₂₇=27!/(3!*24!)=25*13*9=2925 ways to select 3 students.