Answer:
The probability that the pirate misses the captain's ship but the captain hits = 0.514
Step-by-step explanation:
Let A be the event that the captain hits the pirate ship
The probability of the captain hitting the pirate ship, P(A) = 3/5
Let B be the event that the pirate hits the captain's ship
The probability of the pirate hitting the captain's ship P(B) = 1/7
The probability of the pirate missing the captain's ship, P'(B) = 1 - P(B)
P'(B) = 1 - 1/7 = 6/7
The probability that the pirate misses the captain's ship but the captain hits = P(A) * P(B) = 3/5 * 6/7
= 0.514
Answer:
I dont even know
Step-by-step explanation:
too complicated
The school can buy fifteen notebooks and nineteen tablets. 15X7=105 and 5X19=95. 95+105=200. The first thing you want to do is realize that 5Xanything will give you an answer that has a 0 or a five at the end, so you want to find a product by 7 that ends with a 0 or 5 too.
<span>(2n + 2)(2n – 2)
= (2n)^2 -2^2
= 4n^2 - 4
hope it helps</span>
Answer:
D. insufficient data
Step-by-step explanation:
We need to know the number of assignments in each class before we can tell the probability of interest.
__
If we assume the same number of assignments in each class, then 25.1% of on-time assignments were in physics. We note this is not an answer choice, further confirming we have <em>insufficient data</em>.