Answer:
<em><u>The final atmospheric pressure is 5.19 · 10⁴ Pa</u></em>
Step-by-step explanation:
Assuming that the temperature of the air does not change, we can use Boyle's law, which states that for a gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume. In formula,
pV = const.
where p is the gas pressure and V is the volume
The equation can also be rewritten as
p₁ V₁ = p₂ V₂
where in our problem we have:
p₁ = 1.03 · 10₅ Pa is the initial pressure (the atmospheric pressure at sea level)
V₁ = 90.0L is the initial volume
p₂ is the final pressure
V₂ = 175.0L is the final volume
Solving the equation for p2, we find the final pressure:
p₂ = p₁ v₁ divided by V₂ = (1.01 · 10⁵)(90.0) divided by 175.0 = 5.19 · 10⁴ Pa
for the rectangular red paper :
w₁ = width of the red paper = 4 cm
L₁ = length of red paper = 2 w = 2 x 4 = 8 cm
A₁ = area of the red paper = L₁ w₁ = 8 x 4 = 32 cm²
for the rectangular blue paper :
w₂ = width of the blue paper = 3 cm
L₂ = length of blue paper = 7 cm
A₂ = area of the blue paper = L₂ w₂ = 7 x 3 = 21 cm²
area visible is given as
A = A₁ - A₂ = 32 cm² - 21 cm² = 11 cm²
so 11 square units of red paper will be visible on top
I believe the answer is 3/8. The whole portion of employees, which is translated as 8/8 is deducted by 5/8, which is the population of male employees.
Answer:
17/4 kg
Step-by-step explanation:
Sunita has = 10kg of grapes
Quantity given out :
To Reena =3 1/2
7/2 kg
To Anita =2 1/4
9/4 kg
Total quantity of grape given out
7/2+9/4
(14+9)/4
23/4
Quantity left after giving out = Total quantity of grape before giving out minus quantity of grape given out
10/1 - 23/4
40-23)/4
= 17/4 or 4 1/4
Hence, she has 17/4 kg of grape left with her
Answer:
Range = [- 2.5, 0.5] = [ - 5/2, 1/2]
Step-by-step explanation:
Smallest value of cos α = - 1,
largest value of cos α = 1.
When cos 4x = - 1, y=3/2cos4x-1 = 3/2*(-1) - 1 = - 5/2 = - 2 1/2 = - 2.5
When cos 4x = 1, y=3/2cos4x-1 = 3/2*1 - 1 = 1/2 = 0.5
Range = [- 2.5, 0.5] = [ - 5/2, 1/2]
