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2 years ago

What information would verify that LMNO is an isosceles trapezoid? Check all that apply. LN ≅ MO LM ≅ ON LO ≅ MN ∠L ≅ ∠N ∠L ≅ ∠M

Mathematics

2 answers:

Ne4ueva [31]2 years ago

8 0

Answer:

a,c and e

Step-by-step explanation:

FinnZ [79.3K]2 years ago

4 0

Answer:

A, C, and E

Step-by-step explanation:

just did the assignment :)

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The life of a manufacturer's compact fluorescent light bulbs is normal, with mean 12,000 hours and standard deviation 2,000 hour

ikadub [295]

Mean = 12000
Standard Deviation = 2000

We have to find how many standard deviations is 14,500 away from the mean.
This can be achieved by calculating the z-score

Z-score tells us how many standard deviations above or below is a sample value from the mean. A positive z value shows, sample value is above the mean.

z score can be calculated as = (Sample Value - Mean )/Standard Deviation)
So,
Z-score = $\frac{14500-12000}{2000} =1.25$

This means, 14,500 is 1.25 standard deviations above the mean value 12,000.

4 0

2 years ago

Read 2 more answers

In the derivation of the quadratic formula by completing the square, the equation (x+b over 2a)^2=-4ac+b^2 over 4a^2 is created

vredina [299]

Answer:

The result of applying the square root property of equality to this equation is $x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$ .

Step-by-step explanation:

Consider the provided equation.

$\left(x+\dfrac{b}{2a}\right)^2=\dfrac{-4ac+b^2}{4a^2}$

As the above equation is formed by perfect square trinomial so simply applying the square root property as shown:

$\sqrt{(x+\dfrac{b}{2a})^2}=\pm \dfrac{\sqrt{-4ac+b^2}}{\sqrt{4a^2}}\\x+\dfrac{b}{2a}=\pm \dfrac{\sqrt{b^2-4ac}}{2a}$

Isolate the variable x.

$x=-\dfrac{b}{2a}\pm \dfrac{\sqrt{b^2-4ac}}{2a}\\x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Hence, the result of applying the square root property of equality to this equation is $x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$ .

4 0

2 years ago

Read 2 more answers

Solve the equation -10 (g - 6) = -65

Elanso [62]

Step-by-step explanation:

$- 10(g - 6) = - 65 \\ - 10g + 60 = - 65 \\ - 10g = - 125 \\ 10g = 125 \\ g = \frac{25}{2}$

5 0

2 years ago

You have just received an inheritance of $28,000 and would like to invest it into an account. The bank offers two investment pla

grigory [225]

First we need to calculate annual withdrawal of each investment
The formula of the present value of an annuity ordinary is
Pv=pmt [(1-(1+r)^(-n))÷(r)]
Pv present value 28000
PMT annual withdrawal. ?
R interest rate
N time in years
Solve the formula for PMT
PMT=pv÷[(1-(1+r)^(-n))÷(r)]

Now solve for the first investment
PMT=28,000÷((1−(1+0.058)^(−4))
÷(0.058))=8,043.59
The return of this investment is
8,043.59×4years=32,174.36

Solve for the second investment
PMT=28,000÷((1−(1+0.07083)^(
−3))÷(0.07083))=10,685.63
The return of this investment is
10,685.63×3years=32,056.89

So from the return of the first investment and the second investment as you can see the first offer is the yield the highest return with the amount of 32,174.36

Answer d

Hope it helps!

6 0

2 years ago

In general, the probability that it rains on Saturday is 25%. If it rains on Saturday, the probability that it rains on Sunday i

lora16 [44]

Answer:

40%

Step-by-step explanation:

From the given statements:

The probability that it rains on Saturday is 25%.

P(Sunday)=25%=0.25

Given that it rains on Saturday, the probability that it rains on Sunday is 50%.

P(Sunday|Saturday)=50%=0.5

Given that it does not rain on Saturday, the probability that it rains on Sunday is 25%.

P(Sunday|No Rain on Saturday)=25%=0.25

We are to determine the probability that it rained on Saturday given that it rained on Sunday, P(Saturday|Sunday).

P(No rain on Saturday)=1-P(Saturday)=1-0.25=0.75

Using Bayes Theorem for conditional probability:

P(Saturday|Sunday)= $\frac{P(Sunday|Saturday)P(Saturday)}{P(Sunday|Saturday)P(Saturday)+P(Sunday|No Rain on Saturday)P(No Rain on Saturday)}$

= $\frac{0.5*0.25}{0.5*0.25+0.25*0.75}$

=0.4

There is a 40% probability that it rained on Saturday given that it rains on Sunday.

5 0

2 years ago