Answer:
a) Calculate the probability that at least one of them suffers from arachnophobia.
x = number of students suffering from arachnophobia
= P(x ≥ 1)
= 1 - P(x = 0)
= 1 - [0.05⁰ x (1 - 0.05)¹¹⁻⁰
]
= 1 - (0.95)¹¹
= 0.4311999 = 0.4312
b) Calculate the probability that exactly 2 of them suffer from arachnophobia? 0.08666
= P(x = 2)
= (¹¹₂) x (0.05)² x (0.95)⁹
where ¹¹₂ = 11! / (2!9!) = (11 x 10) / (2 x 1) = 55
= 55 x 0.0025 x 0.630249409 = 0.086659293 = 0.0867
c) Calculate the probability that at most 1 of them suffers from arachnophobia?
P(x ≤ 1)
= P(x = 0) + P(x = 1)
= [(¹¹₀) x 0.05⁰ x 0.95¹¹] + [(¹¹₁) x 0.05¹ x 0.95¹⁰]
= (1 x 1 x 0.5688) + (11 x 0.05 x 0.598736939) = 0.5688 + 0.3293 = 0.8981
47 = 50 - 3 or:
47 = Mean - 1 Standard deviation
For normal distribution it means that 4 bags represent 16 % of all samples.
4 bags ------ 16%
x bags ------ 100 %
---------------------------
4 * 100 = x * 16
16 x = 400
x = 400 : 16
x = 25
Answer: 25 bags were probably taken as samples.
He should have worked out 7h(2 - h) first before adding the 3h. (first step)
2nd step he multiplied the 2 by -10h but he also should have multiplied the -h by the -10h ( Distributive law)
Answer:
Her brother catch her at 11 am + 4hour = 15 p.m
Step-by-step explanation:
Given as ;
Speed of Ariel = 45 mph
She left home at 9 a.m
Her brother speed = 60 mph
Her brother left home at 11 a.m
Now from question So As Ariel speed is 45 mph so, after two hours pass , she ahead 90 m .
As her brother travel as 60 mph ,so he travel at ( 60 - 45 )= 15 mph faster
So, with this speed her brother will catch up her at 
= after 4 hour .
Hence her brother catch her at 11 am + 4hour = 15 p.m Answer
