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1 year ago

7

A turtle swims at a speed of 1584 meters per hour. A girl swims at a speed of 1380 millimeters per second how much faster does t

he girl swim than the turtle in centimeters per minutes?

2 answers:

ehidna [41]1 year ago

6 0

Answer:

the girl swims 5640 cm/mins faster

Step-by-step explanation:

d1i1m1o1n [39]1 year ago

5 0

The turtle swims faster. In fact, the turtle swims 812 cm/min faster.

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Kent has a collection of pennies and nickels with a value of 1.98$. the number of pennies he has is five less than twice the num

Alex73 [517]

<span>Kent has a collection of pennies and nickles with a value of $1.98. The number of pennies he has is five less than twice the number of nickles. How many of each coin does Kent have?
----
p + 5n = 198
p = 2n - 5
</span>---
Sub for p
2n-5 + 5n = 198

8 0

2 years ago

Read 2 more answers

Player V and Player M have competed against each other many times. Historical data show that each player is equally likely to wi

Helen [10]

Answer:

0.46 (46%)

Step-by-step explanation:

We have the following data:

- Probability that player V wins the first set:

$p(1)=0.50$

(because the text says the two players are equally likely to win the first set)

- Probability that player V wins the 2nd set if he has won the 1st set:

$p(2|1)=0.60$

So, the probability that player V wins the first 2 sets is:

$p(12)=p(1)\cdot p(2|1)=(0.50)(0.60)=0.30$ (1)

Instead, the probability that player V loses the 2nd set if he has won the 1st set is 0.40 (=1-0.60), so

$p(2^c|1)=0.40$

So, the probabiity that player V winse the 1st set but loses the 2nd set is

$p(12^c)=p(1)\cdot p(2^c|1)=(0.50)(0.40)=0.20$ (2)

Also, we have:

- Probability that player V loses the 1st set:

$p(1^c)=0.50$

- Probability that she will lose the 2nd set in this case is 0.70, it means that the probability that she will win the 2nd set if she lost the 1st set is 0.30, so:

$p(2|1^c)=0.30$

So, the probability that she will lose the 1st set and win the 2nd set is:

$p(1^c2)=p(1^c)\cdot p(2|1^c)=(0.50)(0.30)=0.15$ (3)

Combined together (2) and (3), this means that the probability that player V wins exactly 1 set out of the first two sets is:

$p(1/2)=p(12^c)+p(1^c2)=0.20+0.15=0.35$ (4)

At this point, the probability that she will win the 3rd set is

$p(3)=0.45$

This means that the overall probability that she will win the 3rd set if she won exacty 1 of the first 2 sets is:

$p(1/2,3) = p(1/2)\cdot p(3)=(0.35)(0.45)=0.16$ (5)

So, the overall probability that player V will win a match against player M is the sum of (1) and (5):

$p(W)=p(12)+p(1/2,3)=0.30+0.16=0.46$

5 0

2 years ago

The selling price of a chair is N14 000. The trader gives a 25% discount for cash. What is the cash price?

True [87]

Answer:N10500

Step-by-step explanation:

10%of 14000=1400

20%=1400x2=2800

5%=1400 divided by 2=700

25%=2800+700=3500

14000-3500=10500

hope this helps

5 0

2 years ago

Ramona's backyard is fenced and represented by parallelogram YARD with measures in meters. She installed a 12-meters fence to se

Alisiya [41]

The fencing line x is the height of a rectangle triangle of base = y, hypothenuse of 9 m, so we use Pythagoras theorem to solve:

hyp^2 = height^2 + base^2
9^2 = x^2 + y^2
x^2 = 81 - y^2

we can see that x is also the height of another rectangle triangle of base = 15 - y, hypothenuse of 12 m, so we use Pythagoras theorem to solve:
hyp^2 = height^2 + base^2
12^2 = x^2 + (15 - y)^2

lets expand:
144 = x^2 + 225 - 30y + y^2

substitute x^2 from the first equation in the last:
144 = 81 - y^2 + 225 - 30y + y^2
144 = 81 + 225 - 30y
30y = -144 + 81 + 225
y = 5.4 m

substitute in the fence equation:
x^2 = 81 - y^2
x^2 = 81 - 5.4^2
x = 7.2 m that is the length of the fence

3 0

2 years ago

A cube has an edge of 2 feet. The edge is increasing at the rate of 5 feet per minute. Express the volume of the cube as a funct

Agata [3.3K]

Answer:

$V(m) = (2 + 5m)^3$

Step-by-step explanation:

Given

Solid Shape = Cube

Edge = 2 feet

Increment = 5 feet per minute

Required

Determine volume as a function of minute

From the question, we have that the edge of the cube increases in a minute by 5 feet

<em>This implies that,the edge will increase by 5m feet in m minutes;</em>

Hence,

$New\ Edge = 2 + 5m$

Volume of a cube is calculated as thus;

$Volume = Edge^3$

Substitute 2 + 5m for Edge

$Volume = (2 + 5m)^3$

Represent Volume as a function of m

$V(m) = (2 + 5m)^3$

4 0

2 years ago