Answer:
(13/10)H
got it on khan academy brainliest pls thx uwu
Remember that 30% in fraction form is 33/100
The amount of health points (H) restored would depend on the amount of the current H so it means it would add 30% of the current which we can write as:
(30/100)H
And since it would add that to the current total we can right the current total as:
(100/100)H
So our equation would be
=(30/100)H + (100/100)H
=(130/100)H
=(13/10)H
Answer:

Step-by-step explanation:
<em>Subtract the students who don't have protractors from the students who have mathematical instruments.</em>

For this case we must find the surface area of a rectangular prism.
We have then:

Where,
w: width
l: long
h: height
Substituting values we have:
Answer:
There will be needed 88 in ^ 2 of giftwrap to cover the box
Answer:
a) 2/42
b)16/42
Step-by-step explanation:
a) 2/7 x 1/6 = 2/42
b) (1,2) (1,3) (2,3)
P(1,2) = 2/7 x 3/6 = 6/42
P(1,3) = 2/7 x 2/6 = 4/42
P(2,3) = 3/7 x 2/6 = 6/42
Add all = 6/42 + 4/42 + 6/42 = 16/42
Answer:


Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
Solution to the problem
For this case we select a sample of n =100
From the central limit theorem we know that the distribution for the sample mean
is given by:
So then the sample mean would be:

And the standard deviation would be:
