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Dmitrij [34]
2 years ago
8

In a class, 4/5 of the students have mathematical instruments. 1/4 of these students have lost their protractors. What fraction

of students in the class has protractors?​
Mathematics
2 answers:
Novay_Z [31]2 years ago
6 0

Answer:

\frac{11}{20}

Step-by-step explanation:

\frac{4}{5} - \frac{1}{4}          <em>Subtract the students who don't have protractors from the students who have mathematical instruments.</em>

\frac{11}{20}

lawyer [7]2 years ago
3 0

9514 1404 393

Answer:

  3/5

Step-by-step explanation:

We assume that every student with mathematical instruments who hasn't lost their protractor will have a protractor.

If 1/4 of the students with instruments lost their protractor, then the remaining 3/4 of students with instruments still have their protractors. The fraction of the class with protractors is ...

  (3/4)(4/5) = 3/5

3/5 of the students in the class have protractors.

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Eight less than four times a number is less than 56. What are the possible values of that number
yan [13]
Let unknown number be x.

Given,

4x - 8 < 56

4x < 64

x < 16

Hence, x is any value less than 16.
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2 years ago
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Maxis taking a cross-country road trip. Gas prices vary as the friends travel across the US from $4 dollars per gallon on the ea
Zolol [24]

Answer:

A) The amount of gas they bought on each coast;

East Coast = 35 gallons

Mid-US = 100 gallons

West Coast = 15 gallons

B) The amount of gas they bought on each coast on the return journey;

East Coast = 37 gallons

Mid-US = 116 gallons

West Coast = 21 gallons

Step-by-step explanation:

Complete Question

Maxis taking a cross-country road trip. Gas prices vary as the friends travel across the US from $4 dollars per gallon on the east coast to $3 in the mid-US, to $5 on the west coast.

(a) If they used twice as much gas in the mid-US than on either coast combined, and they spend $515 on gas to purchased 150 gallons of gas, how many gallons of gas did they buy at each price?

The answer to this question is East Coast - 35 gal, Mid-US - 100 gal, West Coast - 15 gal.

(b) On their way back they had more baggage in the car and spend $601 for 174 gallons of gas. Based on the same ratio as in Part (a), how many gallons of gas did they buy at each price? I don't know the answer to this one

Solution

Let the amount of fuel bought on the east coast = x gallons

Let the amount of fuel bought on the mid-coast = y gallons

Let the amount of fuel bought on the west coast = z gallons

a) - They used twice as much gas in the mid-US than on either coast combined

y = 2(x + z) = 2x + 2z (eqn 1)

- They spend $515 on gas to purchase 150 gallons of gas.

Total gallons purchased = x + y + z = 150

Total amount spent = 4x + 3y + 5z = 515

From eqn 1, y = 2x + 2z, inserting this value for y in the 2 other equations

x + y + z = x + 2x + 2z + z = 150

3x + 3z = 150

Divide through by 3

x + z = 50 (eqn *)

4x + 3y + 5z = 4x + 3(2x + 2z) + 5z = 515

4x + 6x + 6z + 5z = 515

10x + 11z = 515 (eqn **)

x + z = 50

10x + 11z = 515

Solving the simultaneous equation,

x = 35 gallons

z = 15 gallons

y = 2x + 2z = 2(35 + 15) = 100 gallons

B) On the return journey, the ratio between x, y and z is still the same, but the total gallons and total amount spent is now different.

They used twice as much gas in the mid-US than on either coast combined

y = 2(x + z) = 2x + 2z (eqn 1)

- They spend $601 on gas to purchase 174 gallons of gas.

Total gallons purchased = x + y + z = 174

Total amount spent = 4x + 3y + 5z = 601

From eqn 1, y = 2x + 2z, inserting this value for y in the 2 other equations

x + y + z = x + 2x + 2z + z = 174

3x + 3z = 174

Divide through by 3

x + z = 58 (eqn *)

4x + 3y + 5z = 4x + 3(2x + 2z) + 5z = 601

4x + 6x + 6z + 5z = 601

10x + 11z = 601 (eqn **)

x + z = 58

10x + 11z = 601

Solving the simultaneous equation,

x = 37 gallons

z = 21 gallons

y = 2x + 2z = 2(37 + 21) = 116 gallons

Hope this Helps!!!

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2 years ago
A field goal kicker makes 4 of 5 extra points during a game . What percent of extra points were made
aleksandrvk [35]
80% of extra points were made.
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2 years ago
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Find the sum and product of the roots of the equation 5x^2+11x-3=0 ?
DanielleElmas [232]
I hope this helps you




disctirminant=b^2-4ac


b=11


a=5


c= -3


disctirminant =11^2-4.5. (-3)


disctirminant =121+60


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x1=-11+ square root of 181/2.5


x2=-11- square root of 181/2.5
5 0
2 years ago
In a survey, the ratio of the number of people who preferred tea to those who preferred coffee was 9:5
kodGreya [7K]

Answer:

45 people prefered coffee, 81 people prefered tea. A total of 126 people were surveyed.

Step-by-step explanation:

Let t be the people who prefer tea, and let c be the people who prefer coffee.

The ratio between tea and coffee is 9:5, thus we have t/c=9/5. Cross products  give us 5t=9c.

Also, we have 36 more people prefer tea than coffee, so we have c+36=t

Thus we have: 5(c+36)=9c

5c+180=9c

180=4c

c=45

c+36=t

45+36=81

5 0
2 years ago
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