Solve the system of inequalities: y + 2x > 3 and y Greater-than-or-equal-to 3.5x − 5 The first inequality, y + 2x > 3, is
in slope-intercept form. The first inequality, y + 2x > 3, has a boundary line. The second inequality, y Greater-than-or-equal-to 3.5x − 5, has a boundary line. Both inequalities have a solution set that is shaded their boundary lines. is a point in the solution set of the system of inequalities.
1 answer:
Answer:
Here's what I get.
Step-by-step explanation:
1. Graphing the system of inequalities
The graph of y + 2x > 3 is in red. All points that satisfy this inequality are in the shaded red area.
The graph of y ≥ 3.5x - 5 is in blue. All points that satisfy this inequality are in the shaded blue area.
Both inequalities have a solution set in the purple shaded area above their boundary lines
2. First inequality
The first inequality, y + 2x > 3, is not in slope-intercept form. The slope-intercept form would be y > -2x + 3.
It has a dashed boundary line to show that points in the line do not satisfy the inequality.
3. Second inequality
The second inequality, y ≥ 3.5x - 5, has a solid boundary line to show that points on it satisfy the inequality.
4. A point in the solution set
The point (1,2) is in the purple shaded solution area for the system. It satisfies both inequalities.
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Answer:
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Step-by-step explanation:
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Answer:
The percentage markup do the boutiques charge their customer is 150%
Step-by-step explanation:
Given as :
The price for hand woven scarves = $ 10
The price of selling by boutiques to customers = $ 25
Let The markup percentage = x
So , markup percentage = × 100
Here The value of selling price ( S.P ) = $ 25
And The value of cost price ( C .P ) = $ 10
So , x = × 100
Or , x = × 100
Or, x = × 100
Or, x = 1.5 × 100
∴ Markup = 150% of cost of sales
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Answer: (1.5, 0)
Step-by-step explanation:
Given : The shape of his satellite can be modeled by where x and y are modeled in inches.
Now,the given equation is a equation of parabola.
Here, coefficient of x is positive, hence the parabola opens rightwards.
On comparing this equation with standard equation , we get
In standard equation, coordinates of focus=(m,0)
Thus for given equation coordinates of focus=(1.5,0)