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LekaFEV [45]
1 year ago
6

Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o

ften. This has the obvious downside of more frequent colds and other illnesses, but it also serves to challenge the immune system of children at a critical stage in their development. A study by Gilham et al. (2005) tested whether social activity outside the house in young children affected their probability of later developing the white blood cell disease acute lymphoblastic leukemia (ALL), the most common cancer of children. They compared 1272 children with ALL to 6238 children without ALL. Of the ALL kids, 1020 had significant social activity outside the home (including day care) when younger. Of the kids without ALL, 5343 had significant social activity outside the home. The rest of the children in both groups lacked regular contact with children who were not in their immediate families.
a.) Is this an experimental or observational study?

b.) What are the proportions of children with significant social activity in children with and without acute lymphoblastic leukemia?

c.) What is the odds ratio for acute lymphoblastic leukemia, comparing the groups with and without significant social activity?

d.) What is the 95% confidence interval for this odds ratio?

e.) Does this confidence interval indicate that the amount of social activity is associated with acute lymphoblastic leukemia? If so, did the children with more social activity have a higher or lower occurence of acute lymphoblastic leukemia?

f.) The researchers interpreted their study results in terms of the differing immune system exposure of the children, but gave several alternative explanations for the pattern. Can you think of any possible cofounding variables?
Mathematics
1 answer:
USPshnik [31]1 year ago
8 0

Answer:

a) This is an Observational Study because in this kind of study investigators observe subjects and measure variables of interest without assigning treatments to the subjects. Here, the Gilham et al. (2005) studied two different groups where no treatment or intervention was done. These groups were independent of each other.

b) proportions of children with significant social activity in children with acute lymphoblastic leukemia = 1020/1272 = 0.80

proportions of children with significant social activity in children without acute lymphoblastic leukemia = 5343/6238 = 0.86

c) Odds ratio can be calculated using the following formula:

OR= \frac{a/b}{c/d}

where: a - Number in exposed group with positive outcome(here this means number of children with significant social activity associated with acute lymphoblastic leukemia)

b- Number of children without social activity having with acute lymphoblastic leukemia

c- Number of children with social activity having without acute lymphoblastic leukemia

d- Number of children without social activity having without acute lymphoblastic leukemia

OR= \frac{1020/252}{5343/895}

OR= 0.6780

d) The 95% confidence interval of this Odds Ratio is 0.5807 to 0.7917.

e) Since the odds ratio lies in this confidence interval indicate that the amount of social activity is associated with acute lymphoblastic leukemia. The children with more social activity have a higher occurrence of acute lymphoblastic leukemia.

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A map shows the town where Niko lives. The actual distance from Niko's house to his school is 3 miles, and measures one-half inc
katrin2010 [14]

Answer:

<u>The distance of the library in the map is 0.67 inches (Rounding to two decimal places)</u>

Step-by-step explanation:

1. Let's review all the information given for solving this question:

Scale factor for the map of the town = 0.5 inches: 3 miles

Distance from Niko's house to his school = 3 miles

Distance from Niko's school to the library = 4 miles

2. Let's find the distance of the library in the map

Distance of the library in the map = Distance of the library * Scale factor

Distance of the library in the map = 4 miles * 0.5 inches:3 miles

Distance of the library in the map = (2 miles * inches)/3 miles

Distance of the library in the map = 2 inches/3 (Miles are cancelled in the numerator and in the denominator)

<u>Distance of the library in the map = 0.67 inches (Rounding to two decimal places)</u>

3 0
2 years ago
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A nurse is preparing to administer dextrose 5% water (D5W) 250 ml IV to infuse over 2 hr. The nurse should set the IV pump to de
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Answer:

the answer is 125

Step-by-step explanation:

I divided 250 and 2

125***ANSWER

4 0
2 years ago
Every morning I take either bus number 5 or bus number 8 to work. Every morning the waiting time for the number 5 is exponential
Simora [160]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

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2 years ago
In circle A shown, BC || DE , mBC=58° and mDE=142°. Determine the measure of ZCFE . Show how you arrived at your answer.
AysviL [449]

Answer:

< CFE = 40°

Step-by-step explanation:

To better understand the solution, see attachment for the diagram.

Given:

BC parallel to DE

Measure of Arc BD = 58°

Measure of Arc DE = 142°

First step: Draw a diameter that passes through the centre of the circle and name it. In this case, the diameter is line ST.

The line ST divides the arc BD and arc DE into half.

That is:

Arc SC = 1/2(arc BC) =1/2(58)

Arc SC = 29°

Arc TE = 1/2(arc DE) =1/2(142)

Arc TE = 71°

Arc SC + Arc CE + Arc TE = 180° (Sum of angles in a semicircle

29° + Arc CE  + 71° = 180°

Arc CE + 100° = 180°

Arc CE = 180-100

Arc CE = 80°

Inscribed angle = 1/2(intercepted angle)

<CFE = 1/2(Arc CE )

<CFE = 1/2(80)

< CFE = 40°

5 0
1 year ago
If the perimeter of a square is 5 feet, how many inches long is each side of the square?
marysya [2.9K]
Well since we know that the perimeter of a square is four times the length of one of its sides. We just have to divide 5 by 4 to get the length of one side:

5feet /4 sides = 1.25 feet

And to finish off, we have to convert feet to inches:

<u>1 foot      </u>= <u>12 inches</u>
1.25 feet    x inches

x inches = 12 inches x 1.25 feet ÷ 1 foot
x inches = 15 inches

Therefore, each side is 15 inches long.

Hope this helps!
3 0
2 years ago
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