Answer:
Step-by-step explanation:
Given
Required
Determine the formula
First, we need to solve common difference (d)
Take n as 2
Represent each function as a sum of the previous
Represent the function as
Reorder
The last page of a book is numbered 764. the book is 3.00 cm thick. what is the average thickness of a sheet of paper in the boo
k, in centimeters? (note that each page has two sides.)
2 answers:
The average thickness of a sheet of paper in the book, in centimeters = 0.007853 cm
<h3><em>Further explanation</em></h3>
The principal is based on the agreement of scientists
The derivative magnitude is a quantity derived from the principal amount
7 main quantities have been determined based on international standards, namely:
- 1. Length, meters (m)
- 2. Time, second (s)
- 3. Mass, kilograms (kg)
- 4. Temperature, kelvin (K)
- 5. Light intensity, candela (cd)
- 6. Electric current, ampere (A)
- 7. Amount of substance, mol (m)
The length of the principal is to indicate the distance between two points in a place
The symbol is usually expressed in l, length
The length measurement can be used by several instruments such as general, caliper length, meter, screw micrometer
The main length of the unit consists of 7 units of other units of length such as inches, miles, yards, feet:
- Kilometer, km
- Hectometer, hm
- Dekameter, dam
- Meter, m
- Decimeter, dm
- centimeter, cm
- millimeters, mm
Each unit descends then multiplied by 10, and if one unit increases then divided by 10
In the question explained that 1 book consists of 764 pages, and because in 1 sheet there are 2-page numbers then there are:
764: 2 = 382 sheets
Because 1 book has a thickness of 3.0 cm, 1 sheet has a thickness:
= 3 cm: 382 sheets
= 0.007853 cm or
= 7,853.10-5 m
<h3><em>Learn more</em></h3>
Find the value of 15.0 N in pounds
the quantity of 0.0075 meters expressed in centimeters
the mass is 41.5 pg
Keywords: book, thick, centimeter
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Answer:
95% of the text messages have length between 23 units and 47 units.
Step-by-step explanation:
We are given the following in the question:
The lengths of text messages are normally distributed.
95% confidence interval:
(23,47)
Thus, we could interpret the confidence interval as:
About 95% of the text messages have length between 23 units and 47 units.
By Empirical rule for a normally distributed data, about 95% of data lies within 2 standard deviations of mean , thus we can write:
Thus, the mean length of text messages is 23 units and standard deviation is 6 units.