Question

The function y = square root sign x is translated using the rule (x, y) → (x – 7, y + 2)to create f(x). What is the domain of f(x)? {x | x > –7} {x | x > 7} {x | x > –2} {x | x > 2} square root x

Answer 1

Answer:

Second option {x | x > 7}

Step-by-step explanation:

We have the function

$y = \sqrt{x}$

We know that the square root of a negative number has no solution in the real ones. Therefore the domain of this function is $x > 0$

When applying the transformation:

$(x, y) \to (x - 7, y + 2)$ we have a translation of the original function in 7 units to the right and 2 units to the top:

$f(x) = \sqrt{x-7} + 2$

In the same way we must guarantee that $(x-7)> 0$

Then $x > 7$.

Therefore the domain of f(x) is {x | x > 7}

Answer 2

a on edge

Step-by-step explanation: