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1 year ago

Which expression is equivalent to 6e+3(e-1)

Mathematics

2 answers:

Dahasolnce [82]1 year ago

5 0

6e + 3(e - 1)

6e + 3e - 3

9e - 3

Katen [24]1 year ago

4 0

Answer: Equivalent expression would be 9e-3.

Step-by-step explanation:

Since we have given that

$6e+3(e-1)$

As we need to simplify the above expression:

First we open the brackets :

$3(e-1)=3e-3$

Now, add it to 6e.

So, it becomes,

$6e+3e-3\\\\=9e-3$

Hence, equivalent expression would be 9e-3.

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What values of b satisfy 3(2b + 3)2 = 36?

meriva

What values of b satisfy 3(2b+3)^2 = 36

we have
3(2b+3)^2 = 36
Divide both sides by 3
(2b+3)^2 = 12
take the square root of both sides
( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3

b1=\frac{\sqrt{12}}{2} -\frac{3}{2}
b1=\sqrt{3} -\frac{3}{2}

b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
therefore

the answer is
the values of b are
b1=\sqrt{3} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}

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1 year ago

Instructions:Select the correct answer from each drop-down menu. The sides of ∆ABC are 30 units, 40 units, and 60 units long. Th

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Answer:

The sides of ∆ABC are 30 units, 40 units, and 60 units long.

The perimeter will be = $30+40+60=130$ units

Given is that ∆ABC and ∆XYZ are similar and the corresponding sides of ∆XYZ are 'r' times as long as the sides of ∆ABC.

So, perimeter of ∆XYZ will be : $130\times r=130r$ units.

----------------------------------------------------------------------------------------

The area of ∆ABC is n square units, so area of ∆XYZ will be :

$\frac{1}{2}(r\times height)(r\times base)$

= $n\times r\times r$

= $nr^{2}$ square units.

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2 years ago

Triangle H N K is shown. Angle H N K is 90 degrees. The length of hypotenuse H K is n, the length of H N is 12, and the length o

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Answer:

Step-by-step explanation:

From the question, we are given a triangle HNK with an angle of 90°

The length of hypotenuse H K is n,

the length of HN is 12

the length of N K is 6.

From the above values, obtained in the question, we can see that this is a right angled triangle.

We are asked to find the length of the hypotenuse.

We can use Pythagoras Theorem of solve for this.

c² = a² + b²

where c = HK = n

a = NK = 6

b = HN = 12

c² = 6² + 12²

c² = 36 + 144

c² = 180

c = √180

c = 13.416407865

Approximately to the nearest whole number = 13

Therefore the value of HK = n = 13

We can also use Law of Cosines as given in the question to solve for this.

a² = b² + c² - 2ac × Cos A

where c = HK = n

a = NK = 6

b = HN = 12

Hence

c² = a² + b² - 2ab × Cos C

c = √ (a² + b² - 2ab × Cos C)

Where C = 90

c = √ 6² + 12² - 2 × 6 × 12 × Cos 90

c = 13.42

Approximately to the nearest whole number ≈ 13

Therefore the value of HK = n = 13

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1 year ago

Which expression is equivalent to 6e+3(e-1)​

Which expression is equivalent to 6e+3(e-1)