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ad-work [718]
1 year ago
8

234,143 rounded to the nearest hundred

Mathematics
2 answers:
Tanzania [10]1 year ago
6 0

Answer:

234,100

Step-by-step explanation:

4 below let him go

5 and above bump him up

if youre looking in the hundreds place (the 1) you look to the right to see what number you have, if you follow the saying ^^ then 4 is let go so you just keep 100.

or if you want to look at it on a number line, 143 is closer to 100 than 200 :)

larisa86 [58]1 year ago
4 0

Answer:

234,100

anything that is below 50 will go down.

Step-by-step explanation:

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You are researching the penguin population in the Falkland Islands. There are 1000 penguins in the beginning of the first year:
kolbaska11 [484]

Answer:

The formula to determine the population of penguins at the end of the 7th year is:

P_7=1.3^7\cdot P_0=6.275\cdot 1000=6275

Step-by-step explanation:

With this information, we know that the initial population at end of year 0 is 1000 penguins.

The first year will born 500 chicks (50% of the population) and also 20% of the total population will die.

We can then model the population for the end of year 1 as:

P_1=P_0+0.5P_0-0.2P_0=1.3P_0

As this dynamic will continue with the years, we can generalize as:

P_2=1.3P_1=1.3\cdot (1.3P_0)=1.3^2P_0\\\\P_n=1.3^nP_0

Then, the value of the population at the end of the 7th year should be:

P_7=1.3^7\cdot P_0=6.275\cdot 1000=6275

8 0
1 year ago
What is the exponential notation for 262,144
7nadin3 [17]

since there is always a decimal at the end of every value so :

           = 262144.0 

        you move the decimal backwards if there is no decimal between the value. you place the decimal after the 1st digit, you will also count the digits you have passed : 

         = 2.62144 X 10^5 

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7 0
1 year ago
Read 2 more answers
An investor believes that investing in domestic and international stocks will give a difference in the mean rate of return. They
arlik [135]

Answer:

So on this case the 90% confidence interval would be given by -4.137 \leq \mu_1 -\mu_2 \leq 2.087  

For this case since the confidence interval for the difference of means contains the 0 we can conclude that we don't have significant differences at 10% of significance between the two means analyzed.

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =2.0233 represent the sample mean 1  

\bar X_2 =3.048 represent the sample mean 2  

n1=15 represent the sample 1 size  

n2=15 represent the sample 2 size  

s_1 =4.893387 population sample deviation for sample 1  

s_2 =5.12399 population sample deviation for sample 2  

\mu_1 -\mu_2 parameter of interest at 0.1 of significance so the confidence would be 0.9 or 90%

We want to test:

H0: \mu_1 = \mu_2

H1: \mu_1 \neq \mu_2

And we can do this using the confidence interval for the difference of means.

Solution to the problem  

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:  

\bar X_1 -\bar X_2 =2.0233-3.048=-1.0247

The degrees of freedom are given by:

df = n_1 +n_2 -2 = 15+15-2=28  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,28)".And we see that t_{\alpha/2}=\pm 1.701  

Now we have everything in order to replace into formula (1):  

-1.0247-1.701\sqrt{\frac{4.893387^2}{15}+\frac{5.12399^2}{15}}=-4.137  

-1.0247+1.701\sqrt{\frac{4.893387^2}{15}+\frac{5.12399^2}{15}}=2.087  

So on this case the 90% confidence interval would be given by -4.137 \leq \mu_1 -\mu_2 \leq 2.087  

For this case since the confidence interval for the difference of means contains the 0 we can conclude that we don't have significant differences at 10% of significance between the two means analyzed.

4 0
1 year ago
If terri were stretching 4 days per week, how many days per week would she need to stretch to increase her frequency variable? 1
Olin [163]

Answer:

3 days is the right answer!!!!! good luck

Step-by-step explanation:


4 0
1 year ago
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Answer:

C. 270 grams

Step-by-step explanation:

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P_t=P_oe^{rt}

Where:

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Given the size at t=2 and at t=0, we substitute in the growth function to solve for r:

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P_t=P_oe^{rt}\\\\=10e^{6\times \frac{In \ 3}{2}}\\\\=270\ grams

Hence, the bacteria's size at t=6 is 270 grams

8 0
1 year ago
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