Just so u know, ur output value is f(x) and ur input value is x
f(x) = -2x^2 - 3x + 5....when ur input value(x) is -3
f(-3) = -2(-3^2) - 3(-3) + 5 =
f(-3) = -2(9) + 9 + 5
f(-3) = -18 + 14
f(-3) = -4 <==
You don't list the "sums listed below" but I can still help you.
There are 6 ways to get a sum of 7 using a pair of dice:
1+6
6+1 You might be asking why 2+5 isn't the same as 5+2
2+5 Imagine the dice are different colors. Is a red 2 and green 5 the
5+2 same as a green 2 and red 5? (No, it's not)
3+4
4+3
You need two numbers that also provide 6 ways to win. One pair that would work is 11 and 9 There are two ways to make 11 (5+6) and (6+5) and there are four ways to make 9 (3+6), (6+3) (4+5) and (5+4) - that's a total of six ways. So to balance your friend's 7 - you could go for sums of 11's and 9's. Check the choices you were given and find the numbers (it could be three numbers like 2,3, and 12) that give you 6 ways to win.
Here are the numbers and their ways
Sum of the dice Ways to get it
2 1
3 2
4 3
5 4
6 5
7 6
8 5
9 4
10 3
11 2
12 1
Answer:
The expected number of coupon is 
Step-by-step explanation:
From the question we are told that
The probability that a $10 coupons delivered by mail will be redeemed is p = 0.16
The sample size is n = 10
Generally the expected number of coupons that will be redeemed is mathematically represented as
=> 
=>
