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n200080 [17]
2 years ago
8

there are 254 counties in Texas. Zane rounds the number of counties to the nearest ten. What is the difference between the actua

l number of counties and Zane's rounded number?
Mathematics
2 answers:
andrezito [222]2 years ago
5 0

Answer:

Difference between the actual number of counties and Zane's rounded number is:

4

Step-by-step explanation:

There are 254 counties in Texas.

Zane rounds the number of counties to the nearest ten.

According to Zane number of countries in Texas=250

Difference between the actual number of counties and Zane's rounded number= 254-250

           =4

Hence, difference between the actual number of counties and Zane's rounded number is:

4

Brums [2.3K]2 years ago
3 0
4...................
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The sum of 48 and itself its half and half of the hal is added to 18​
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Answer:

150

Step-by-step explanation:

We are carrying out Addition

a) The sum of 48 and itself

= 48 + 48 = 96

b) Its half and half of the half

96 + (1/2 × 48) + (1/2 ×( 1/2 × 48)

= 96 + 24 +(1/2 × 24)

= 96 + 24 + 12

= 132

c) is added to 18

= 132 + 18

= 150

Therefore, the sum of 48 and itself, its half and half of the half is added to 18 is 150

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2 years ago
See You Later Based on a Harris Interactive poll, 20% of adults believe in reincarnation. Assume that six adults are randomly se
REY [17]

Answer:

a) There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b) 0.0064% probability that all of the selected adults believe in reincarnation.

c) There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d) Since P(X \geq 5) < 0.05, 5 is a significantly high number of adults who believe in reincarnation in this sample.

Step-by-step explanation:

For each of the adults selected, there are only two possible outcomes. Either they believe in reincarnation, or they do not. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 6, p = 0.2

a. What is the probability that exactly five of the selected adults believe in reincarnation?

This is P(X = 5).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{6,5}.(0.2)^{5}.(0.8)^{1} = 0.0015

There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b. What is the probability that all of the selected adults believe in reincarnation?

This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.2)^{6}.(0.8)^{0} = 0.000064

There is a 0.0064% probability that all of the selected adults believe in reincarnation.

c. What is the probability that at least five of the selected adults believe in reincarnation?

This is

P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564

There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d. If six adults are randomly selected, is five a significantly high number who believe in reincarnation?

5 is significantly high if P(X \geq 5) < 0.05

We have that

P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564 < 0.05

Since P(X \geq 5) < 0.05, 5 is a significantly high number of adults who believe in reincarnation in this sample.

5 0
2 years ago
Which is an x-intercept of the continuous function in the table?
Ad libitum [116K]

Answer:

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Step-by-step explanation:

The x-intercept is the point where the graph of the function meets the x-axis.

At x-intercept, y=0 or f(x)=0

So look through the table and find where f(x)=0.

From the table, f(x)=0 at x=3.

We write this as an ordered pair.

Therefore the x-intercept is (3,0)

The correct choice is B.

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Answer:

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Step-by-step explanation:

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2 years ago
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