To answer this question, you need to makes the unit of the smartphone screen same. In this case, phone A is using decimal and phone B is using a fraction. You can use which was easier.
Let's try to use decimal. Then you need to convert phone B fraction width into decimal width. The calculation would be: 5cm + 1/3cm= 5 cm + 0.333cm= 5.333cm
From here it clear that phone B has a wider screen than phone A.
Yes, 0.1 is less than 5.00.
5.00 is a whole number, while 0.1 is less than that, so yes, you were correct.
Have a nice day! :)
Idk because you did not say yes you did how many sides there were
Answer:
![g(x) = \sqrt[3]{x-1} - 2](https://tex.z-dn.net/?f=%20g%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx-1%7D%20-%202%20)
Step-by-step explanation:
We want to find h and k in:
![g(x) = \sqrt[3]{x-h} + k](https://tex.z-dn.net/?f=%20g%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx-h%7D%20%2B%20k%20)
At the inflection point, the second derivative is equal to zero, so:


Then x - h = 0.
Inflection point is located at (1, -2), replacing this x value we get:
1 - h = 0
h = 1
We know that the point (-2.5, -3.5) belongs to the function, so:
![-3.5 = \sqrt[3]{-2.5-1} + k](https://tex.z-dn.net/?f=%20-3.5%20%3D%20%5Csqrt%5B3%5D%7B-2.5-1%7D%20%2B%20k%20)
k ≈ -2
All data, used or not, are shown in the picture attached.