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Debora [2.8K]
1 year ago
15

During an experiment, Juan rolled a six-sided number cube 18 times. The number two occurred four times. Juan claimed the experim

ental probability of rolling a two was approximately StartFraction 1 over 9 EndFraction. Which of the following is true about Juan’s claim?
Juan's claim is incorrect. The correct experimental probablilty is StartFraction 2 over 9 EndFraction.
Juan's claim is incorrect. The correct experimental probablilty is One-third.
Juan's claim is incorrect. The correct experimental probablilty is StartFraction 4 over 9 EndFraction.
Juan’s claim is correct.
Mathematics
2 answers:
Maru [420]1 year ago
8 0

Answer:

1) Juans claim is incorrect. The correct experimental probablilty is 2/9

Step-by-step explanation:

stiks02 [169]1 year ago
3 0

Answer:

a

Step-by-step explanation:

Juan's claim is incorrect. The correct experimental probablilty is 2/9

You might be interested in
Farmer McCoy can plant either corn or soybeans. The probabilities that the next harvest prices will go up, stay the same, or go
Snezhnost [94]

Answer:

McCoy should plant soybeans

Step-by-step explanation:

Thinking process:

Let the two crops be corn and soybeans as indicated.

The profit margin for corn will be $ 30 000. However, the loss will be:

$ 35 000 - $ 30 000 = $ 5 000

For the soybean, the  profit margin will be $ 10 000.

The loss will be $ 5 000

The net balance will be given as: $ 5 000 - $ 10 000 = - $ 5 000. (This represents a gain)

Thus, soybean will be more profitable.

4 0
2 years ago
At a rally attended by 520 people, 30% were fantes, 25% were ewes, 15% were nzemas, 20% were gas and the rest were gonjas. How m
mariarad [96]

Answer:

No. of gonjas = 52

No. of more nzemas than fantes = 78

Step-by-step explanation:

Total no. of people = 520

No. of fantes = \frac{30}{100} × 520

No. of fantes = 156

No. of ewes = \frac{25}{100} × 520 = 130

No. of nzemas = \frac{15}{100} × 520 = 78

No. of gas = \frac{20}{100} × 520 = 104

No. of gonjas = 520 - (156 + 130 + 78 + 104) = 52

No. of fantes = 156

No. of nzemas = 78

No. of more nzemas than fantes = 156 - 78 = 78

Pie chart of the following problem is shown below.

5 0
2 years ago
Read 2 more answers
A triangle with exterior angles is shown. A triangle sits on a line and forms 2 exterior angles on the left and right of the tri
NARA [144]

Answer:

Option 3.

Step-by-step explanation:

It is given that a triangle sits on a line and forms 2 exterior angles on the left and right of the triangle of (2h) degrees.

The top interior angle of the triangle is 40 degrees.

\angle BAC=40

From the given figure it is clear that

\angle ABC+2h=180               (Supplementary angle)

\angle ABC=180-2h

\angle ACB+2h=180               (Supplementary angle)

\angle ACB=180-2h

According to the angle sum property of triangle, the sum of all interior angles of a triangle is 180 degree.

\angle ABC+\angle ACB+\angle BAC=180

(180-2h)+(180-2h)+40=180

Combine like terms.

(180+180+40)+(-2h-2h)=180

400-4h=180

-4h=180-400

-4h=-220

Divide both sides by -4.

h=\frac{-220}{-4}

h=55

The value of h is 55.

Therefore, the correct option is 3.

8 0
2 years ago
Read 2 more answers
The parent function f(x) = x3 is transformed to g(x) = (x – 1)3 + 4. Identify the graph of g(x).
Dominik [7]

we have f(x)=x^3 which is a cubic function.

and =(x-1)^3+4.

from f(x) and g(x) we know that both are cubic and g(x) has shrink of 1 and up by 4 units in x axis .

4 0
2 years ago
Read 2 more answers
Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. A = 46°, b
horrorfan [7]
We will use the law of cosines
<span>side a² = b² + c² -2bc • cos(A)
</span><span>side a² = 729 + 196 -2*27*14 * cos (46)
</span><span>side a² = 925 -(756 * 0.69466)
</span>side a² = <span><span>399.83704 </span>
side a = </span><span><span><span>19.995925585 </span> </span> </span>
We could round that to 20
a = 20 b = 27 c =14

We can calculate a triangle's area when we know all 3 sides by using Heron's Formula
<span>area = square root (s • (s - a) • (s - b) • (s - c))

where s is the semi-perimeter </span>
semi-perimeter<span> = (side a + side b + side c) ÷ 2</span>
s = (20 + 27 + 14) / 2
s = 30.5
Now we use Heron's Formula
area = square root (s • (s - a) • (s - b) • (s - c))
area = square root (30.5 • (<span>30.5 - 20) • (</span><span>30.5 - 27) • (</span><span>30.5 - 14))</span>
area = square root (30.5 • (10.5) • (3.5) • (<span>16.5))</span>
<span>area = square root (18494.4375)
</span> <span><span><span>area = 135.9942553934  </span> </span> </span>which rounds to
136 square feet
Source:
http://www.1728.org/triang.htm

 




7 0
1 year ago
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