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Debora [2.8K]
2 years ago
15

During an experiment, Juan rolled a six-sided number cube 18 times. The number two occurred four times. Juan claimed the experim

ental probability of rolling a two was approximately StartFraction 1 over 9 EndFraction. Which of the following is true about Juan’s claim?
Juan's claim is incorrect. The correct experimental probablilty is StartFraction 2 over 9 EndFraction.
Juan's claim is incorrect. The correct experimental probablilty is One-third.
Juan's claim is incorrect. The correct experimental probablilty is StartFraction 4 over 9 EndFraction.
Juan’s claim is correct.
Mathematics
2 answers:
Maru [420]2 years ago
8 0

Answer:

1) Juans claim is incorrect. The correct experimental probablilty is 2/9

Step-by-step explanation:

stiks02 [169]2 years ago
3 0

Answer:

a

Step-by-step explanation:

Juan's claim is incorrect. The correct experimental probablilty is 2/9

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Alex bought a new easy chair for $399. She bought it on the '12 months is the same as cash' plan. The contract stated that if no
jek_recluse [69]

Answer:

$ 454.86 : $33.25

Step-by-step explanation:

1.

Alex bought the new easy chair for $ 399 .

If she pays the amount in 13th month. So,  she has to pay the interest of 1 month too , which is, = $ \frac {399 \times 14}{100}

                                    =  $ 55.86

So, total amount she has to pay for the chair,

                       = (cost price of the chair + interest)

                       = $ (399 + 55.86)

                       = $ 454.86  (answer)

2.    

If she wants to pay the amount within the 12 months, so that she doesn't have to pay the interest,  her budget for that for each month will be ,

                               $ \frac {399}{12}

                               = $ 33. 25  (answer)

5 0
2 years ago
10 POINTS AND WILL GIVE BRAINLIEST
madam [21]

The final value of the car will be given by:

final = origamt(1 - .20) to the 4th power. The car will retain therefore,only 80% of its original value from the preceding year for each of the 4 years starting with an original value of $35000.

The calculation is

final \:  value \\  = (35000) {(.8)}^{4}  \\  = 35000 \times .4096 \\  =

A measely $14,336!

7 0
2 years ago
Emi computes the mean and variance for the population data set 87, 46, 90, 78, and 89. She finds the mean is 78. Her steps for f
stiks02 [169]

Answer:

135.6

i think

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Why is sin(20) = sin(160) = -sin(200) = -sin(340)?
AveGali [126]
Because they're all the same distance from the x axis on a coordinate plane. Also, remember that in quadrant I, all trig values are positive. In Q II, only sine and cosecant are positive. In Q III, only tangent and cotangent are positive. In Q IV, only cosine and secant are positive. Think of it as <u>A</u>ll <u>S</u>tudents <u>T</u>ake <u>C</u>alculus.
6 0
2 years ago
Read 2 more answers
Assume that the ages for first marriages are normally distributed with a mean of 26 years and a standard deviation of 4 years. W
Snowcat [4.5K]

Answer:

0.7743

Step-by-step explanation:

Mean of age = u = 26 years

Standard Deviation = \sigma = 4 years

We need to find the probability that the person getting married is in his or her twenties. This means the age of the person should be between 20 and 30. So, we are to find P( 20 < x < 30), where represents the distribution of age.

Since the data is normally distributed we can use the z distribution to solve this problem. The formula to calculate the z score is:

z=\frac{x-u}{\sigma}

20 converted to z score will be:

z=\frac{20-26}{4}=-1.5

30 converted to z score will be:

z=\frac{30-26}{4}=1

So, now we have to find the probability that the z value lies between -1.5 and 1.

P( 20 < x < 30) = P( -1.5 < z < 1)

P( -1.5 < z < 1 ) = P(z < 1) - P(z<-1.5)

From the z-table:

P(z < 1) = 0.8413

P(z < -1.5) =0.067

So,

P( -1.5 < z < 1 ) = 0.8413 - 0.067 = 0.7743

Thus,

P( 20 < x < 30) = 0.7743

So, we can conclude that the probability that a person getting married for the first time is in his or her twenties is 0.7743

6 0
2 years ago
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