Answer:
$95.78
Step-by-step explanation:
f(t) = 300t / (2t² + 8)
t = 0 corresponds to the beginning of August. t = 1 corresponds to the end of August. t = 2 corresponds to the end of September. So on and so forth. So the second semester is from t = 5 to t = 10.
$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt
$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt
$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt
$T₂ = 75 ln(t² + 4) |₅¹⁰
$T₂ = 75 ln(104) − 75 ln(29)
$T₂ ≈ 95.78
Answer:
B) 5 (x minus 3)
C) 4 x + 3 y minus 15 minus 3 y + x
E) Negative 20 minus 3 x + 5 + 8 x
tep-by-step explanation:
5x minus 15
5x - 15
5(x - 3)
4 x + 3 y minus 15 minus 3 y + x
4x + 3y - 15 - 3y + x
5x - 15
Negative 20 minus 3 x + 5 + 8 x
-20 - 3x + 5 + 8x
5x - 15
m • (g4c - 3)
(1):g4 was replaced by g^4.
Pulling out like terms:
2.1:Pull out like factors:
g4cm - 3m = m • (g4c - 3)
Trying to factor as a Difference of Squares :
2.2:Factoring: g4c - 3
I think about 52 bags
2 kilometers = 2,000 grams
2, 000/ 38 = 52. repeated decimal(which would be the amount leftover)
I believe the answer would be 52 bags.
