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Anarel [89]
2 years ago
6

Find the missing term. () + (7 − 3i) + (5 + 9i) + 13i = 10 − 5i.

Mathematics
2 answers:
kotegsom [21]2 years ago
5 0
X + (7 - 3i) + (5 + 9i) + 13i = 10 - 5i

Subtract 13i from both sides

x + (7 -3i) + (5 + 9i) = 10 - 18i

Subtract (5 + 9i). MAKE SURE YOU SUBTRACT 9i TOO. In other words, distribute the negative and subtract 5 and 9i at the same time.

x + (7 - 3i) = 5 - 27i

Do the same with (7 - 3i). You'll be adding 3i since -(-3i) = 3i.

x = -2 - 24i
Archy [21]2 years ago
3 0

Answer:

the missing term is (-2-24i)

Step-by-step explanation:

Let

(x+yi)------> the missing term

we have

(x+yi)+(7-3i)+(5+9i)+13i=10-5i

Combine like terms in the left side

(x+7+5)+(yi-3i+9i+13i)=10-5i

(x+12)+(yi+19i)=10-5i

Solve the system of equations

x+12=10 ------> equation A

x=10-12=-2

yi+19i=-5i ------> equation B

yi=-5i-19i=-24i

the missing term is (-2-24i)

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Answer:

A.  f(s) = 2s + 34

B. Mole

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c. f(s) = 2s + 54

3 0
2 years ago
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RUDIKE [14]

<u>Answer:</u>

\simeq 820 feet

<u>Step-by-step explanation:</u>

He has asked me to move the finish line 0.25 km forward

Now,

we know that

1 km = 0.621371 mile

⇒ 0.25 km = 0.25 \times 0.621371 mile  

                   = 0.25 \times 0.621371 \times 1760 \times 3 feet

(since 1760 yards = 1 mile and 3 feet = 1 yard)

                    = 820.20972 feet

                   \simeq 820 feet . (Answer)

8 0
2 years ago
Q13. A stone is dropped from a height of 5 km. The distance it falls through varies directly with the
Simora [160]
I’m not sure but I think it might be C so sorry if it’s wrong
8 0
2 years ago
Read 2 more answers
In a large​ city, 6060​% of people pass the​ drivers' road test. suppose that every​ day, 300300 people independently take the t
erma4kov [3.2K]
A) 180 would be expected to pass.
B) The standard deviation is 4.
C) 95% of people would fall between 172 and 188.
D) Yes, this is more than 3 standard deviations below the mean.

Explanation
A) Multiply the probability by the sample size:
0.6(300) = 180

B) Standard deviation is found by:
√n(p)(1-p)
For our data, we have:
√300(0.6)(0.4) = 4

C) Two standard deviations below the mean is 180-2(4) = 172; two standard deviations above the mean is 180+2(4)= 188.

D) Three standard deviations below the mean is 180-3(4) = 168; 134 is more than this below the mean.  99.7% of data fall within 3 standard deviations of the mean; 0.15% fall below this point, so yes, this is unusually low.
8 0
2 years ago
Senior management of a consulting services firm is concerned about a growing decline in the firm’s weekly number of billable hou
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Answer:  (45.79, 51.21)

Step-by-step explanation:

Given : Significance level : \alpha: 1-0.99=0.01

Sample size : n= 51 , which is a large sample (n>30), so we use z-test.

Critical value: z_{\alpha/2}=2.576

Sample mean : \overline{x}= 48.5\text{ hours}

Standard deviation : \sigma=7.5\text{ hours}

The confidence interval for population means is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

i.e. 48.5\pm(2.576)\dfrac{7.5}{\sqrt{51}}

i.e.48.5\pm2.70534112234\\\\\approx48.5\pm2.71\\\\=(48.5-2.71, 48.5+2.71)=(45.79, 51.21)

Hence, 99% confidence interval for the standard deviation of the number of hours this firm’s employees spend on work-related activities in a typical week =  (45.79, 51.21)

7 0
2 years ago
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