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marshall27 [118]
1 year ago
7

A 4/7 inch pipe is to be shortened to 3/8 inch. How much must be removed?

Mathematics
1 answer:
11Alexandr11 [23.1K]1 year ago
6 0

11/56 inches or 0.196 inches must be removed.

The pipe measures 4/7 inches but needs to be reduced to 3/8 inches.

In order to find out the inches to be removed, you must subtract the length that the pipe should be from the length that it currently is.

<em>Length to be removed = 4/7 - 3/8</em>

You need a common denominator so find the lowest common factor of both denominators:

= 56

In the shared fraction, multiply the numerator by the number you get when you divide 56 by the denominator.

= 56/7 = 8                                      8 x 4 = 32

= 56 / 8 = 7                                    7 x 3 = 21

= (32 - 21) / 56

= 11 / 56 inches

= 0.196 inches

In conclusion, 11/56 inches must be removed to get the pipe to 3/8 inches

<em>Find out more at brainly.com/question/4681199.</em>

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Can I have help on this question, please?
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A local PTA runs a fundraiser, selling lottery tickets for $5, offering 1 first prize of $100 and 5 second prizes worth $20 each
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t​ Technodynamics, Inc., a​ randomly-selected hiring committee of 3 people is formed from a group of 4 employees in marketing an
atroni [7]

Answer: a) 0.25, b) 0.78, c) 0.71

Step-by-step explanation:

Since we have given that

Number of employees in marketing = 4

Number of employees in management = 7

We need to hire committee of 3 people.

​a) Find the probability that the committee has exactly 2 employees from marketing.

So, Probability becomes

\dfrac{^4C_2\times ^7C_1}{^{11}C_3}\\\\=\dfrac{42}{165}\\\\=0.25

​b) Find the probability that the committee has at least one employee from marketing.

P(x\geq 1)=1-P(x=0)\\\\P(x\geq 1)=1-\dfrac{^7C_3}{^{11}C_3}=1-0.212=0.78

c) Find the probability that the committee has at most one employee from management.

P(x\leq 1)=P(x=0)+P(x=1)\\\\P(x\leq 1)=\dfrac{^7C_3}{^{11}C_3}+\dfrac{^7C_2\times ^4C_1}{^{11}C_3}\\\\P(x\leq 1)=0.21+0.50=0.71

Hence, a) 0.25, b) 0.78, c) 0.71

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