Answer:
The measure of angle HBC is m∠HBC=61°
Step-by-step explanation:
In this problem we have that
The line BH bisects angle EBC,
see the attached figure to better understand the problem
then
m∠EBC=m∠EBH+m∠HBC
m∠EBH=m∠HBC
so
m∠EBC=2(m∠EBH)
substitute the given values and solve for a
<em>Find the measure of angle EBH</em>
m∠EBH=(4(4)+45)=61°
Remember that
m∠EBH=m∠HBC
therefore
The measure of angle HBC is m∠HBC=61°
We can solve this equation by using the Square Root Method.
First, take the square root of each side of the equation:
(x-8)^2 = 144 becomes x-8 = 12
Then add 8 to both sides.
x=20
The original lawn was d. 20 feet by 20 feet.
Answer:
The width of the pathway is:
Step-by-step explanation:
To identify the width of the pathway, you must remember the area formula of a rectangle:
- Area of a rectangle = length * width.
From which the width can be cleared:
- Width of a rectangle = area / length.
We know that the length of the terrain was not modified since the pathway is in the perimeter of the rectangle (16 m) and that the new area is 240 m^2, so we only have to replace the cleared formula:
- Width of a rectangle = 240 m^2 / 16 m = 15 m.
The new width is equal to 15 meters, but since the question is not the total width but the width of the pathway, the width of the previously provided land must be subtracted from the value obtained.
- <u>Pathway width = Total width - Garden width.
</u>
- <u>Pathway width = 15m - 8m = 7 meters.</u>
Answer:
2. 13
Step-by-step explanation:
The least number of classes need for all of the students to be registered in a class is 13 since you want all of the stuednts to be registered so no one should be left out. If we do 12*12 (12 students in each class and there are 12 classes), that would only let 144 students take the swimming classes and 8 students would be left out. We don't want that though since we want all of the students to be registered. So let's go to 12*13 (12 students in each class and there are 13 classes), that would let 156 students take the swimming class. 156>152 so therefore, 13 classes would allow for all 152 students to be registered and it is the least number of classes needed for all the students to be registered in a class (plus you would have 4 seats left for anyone who wants to register in the future but the remainder doesn't matter).
