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2 years ago

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On a coordinate plane, the x-axis is labeled Minutes and the y-axis is labeled Distance (in blocks). Point A is (5, 8), point B

is (10, 16), point C is (15, 24), point D is (24, 13). Jose has been keeping a record of the distance he bikes and the time it takes him. He travels at the same unit rate each time and plots the distances for particular times. Which point on the graph did Jose plot incorrectly if he is representing a proportional relationship?

3 answers:

Ipatiy [6.2K]2 years ago

5 0

Answer:

D

Step-by-step explanation:

I Just got it wrong on another answer and this one was right on Ede 2020

Guest

1 year ago

what is it

Guest

1 year ago

what is it

Readme [11.4K]2 years ago

3 0

Answer:

B is your answer ~Ticci Toby~

Step-by-step explanation:

Guest

1 year ago

its not

Guest1 year ago

0 0

The answer is, D
just type in d it's the answer

Guest

1 year ago

in edgenuity

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Marley drives to work every day and passes two independently operated traffic lights. The probability that both lights are red i

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Let event A be the first light being red.
Let event B be the second light being red.

P(A) = 0.48
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P(B) = 0.35 / P(A)
P(B) = 0.35 / 0.48
P(B) = 0.73

Since the lights are independent, P(B|A) = P(B) therefore d is the correct answer.

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Oscar recorded the amount of his monthly electric bill for the first 11 months of the year. An ordered list of the amount in dol

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baker has 5\dfrac145 4 1 5, start fraction, 1, divided by, 4, end fraction pies in her shop. She cut the pies in pieces that a

kupik [55]

Answer:

The answer is "She cut a total of 42 pieces of pie".

Step-by-step explanation:

Given :

Total pie= $5 \frac{1}{4}$

cut pie = $\frac{1}{8}$

The number of pieces of the pie she has=?

Solve the mixed fraction value:

$\to 5 \frac{1}{4}= \frac{21}{4}$

If she cuts the pieces into the entire pie, that is = $\frac{1}{8}$

So, the equation is:

$\to \frac{21}{4} = \frac{1}{8} \times x$

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A waiter at a restaurant has diarrhea what should happen?

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1 year ago

Determine the area (in units2) of the region between the two curves by integrating over the x-axis. y = x2 − 24 and y = 1

astra-53 [7]

Answer:

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

Step-by-step explanation:

This case represents a definite integral, in which lower and upper limits are needed, which corresponds to the points where both intersect each other. That is:

$x^{2} - 24 = 1$

Given that resulting expression is a second order polynomial of the form $x^{2} - a^{2}$ , there are two real and distinct solutions. Roots of the expression are:

$x_{1} = -5$ and $x_{2} = 5$ .

Now, it is also required to determine which part of the interval $(x_{1}, x_{2})$ is equal to a number greater than zero (positive). That is:

$x^{2} - 24 > 0$

$x^{2} > 24$

$x < -4.899$ and $x > 4.899$ .

Therefore, exists two sub-intervals: $[-5, -4.899]$ and $\left[4.899,5\right]$ . Besides, $x^{2} - 24 > y = 1$ in each sub-interval. The definite integral of the region between the two curves over the x-axis is:

$A = \int\limits^{-4.899}_{-5} [{1 - (x^{2}-24)]} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} [{1 - (x^{2}-24)]} \, dx$

$A = \int\limits^{-4.899}_{-5} {25-x^{2}} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} {25-x^{2}} \, dx$

$A = 25\cdot x \right \left|\limits_{-5}^{-4.899} -\frac{1}{3}\cdot x^{3}\left|\limits_{-5}^{-4.899} + x\left|\limits_{-4.899}^{4.899} + 25\cdot x \right \left|\limits_{4.899}^{5} -\frac{1}{3}\cdot x^{3}\left|\limits_{4.899}^{5}$

$A = 2.525 -2.474+9.798 + 2.525 - 2.474$

$A = 9.9\,units^{2}$

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

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