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miskamm [114]
2 years ago
12

Amber believes triangle ABC and triangle GFE are congruent. She has recorded the measures of some of the angles and the lengths

of some of the sides in the triangles below.
What additional measurement would support Amber’s hypothesis?
a.The measure of c is 32
b.The measure of c is 40
c.The measure of c is 50
d.The measure of c is 90

Mathematics
2 answers:
-BARSIC- [3]2 years ago
8 0

Answer:

B for the people that dont wann read all that

Step-by-step explanation:

just took tha edg test

Nostrana [21]2 years ago
6 0
If the triangles are congruent, the angle opposite the 32 cm side will have the same measure as angle E, 40°. An appropriate choice for this question is ...
  b. The measure of c is 40.


_____
In actual fact, the triangles not only are not congruent, they cannot exist. The total of sides FG and FE (82 cm) is less than the length of side GE (38 in). 82 cm is about 32.3 inches, about 5.7 inches too short.

Even if you overlook the units problem, the sum of squares of the sides of the triangle is 32² +38² = 2468, somewhat short of 50² = 2500. That is, the largest angle is slightly more than 90°. It is closer to 90.754° ≈ 91°.

You can label a diagram any way you want, but that doesn't mean the numbers are consistent or sensible.
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If $a$, $b$, $c$, and $d$ are replaced by four distinct digits from $1$ to $9$, inclusive, then what's the largest possible valu
katrin [286]

Answer:

the combination of numbers must then be:

9.7 + 8.6 which results to 18.3

9.6 + 8.7 yields 18.3 as well.

5 0
1 year ago
Coordinates, gradient and tangent work (see image).
Ivenika [448]

Answer:

a) P(x,2x^2-5),\ Q(x+h,2(x+h)^2-5)

b) 4x+2h

c) 4x

Step-by-step explanation:

Given the curve

y=2x^2-5

a) If the x-coordinate of P is x, then the y-coordinate is 2x^2-5, so point P has coordinates (x,2x^2-5)

If the x-coordinate of Q is x+h, then the y-coordinate is 2(x+h)^2-5 so point Q has coordinates (x+h,2(x+h)^2-5)

b) The gradient of the secant RQ is

\dfrac{y_Q-y_P}{x_Q-x_P}\\ \\=\dfrac{(2(x+h)^2-5)-(2x^2-5)}{(x+h)-x}\\ \\=\dfrac{2(x+h)^2-5-x^2+5}{x+h-x}\\ \\=\dfrac{2(x+h)^2-2x^2}{h}\\ \\=\dfrac{2x^2+4xh+2h^2-2x^2}{h}\\ \\=\dfrac{4xh+2h^2}{h}\\ \\=4x+2h

c) If h\rightarrow 0, then the gradient 4x+2h\rightarrow 4x

5 0
1 year ago
4abc + (-9abc) + 10d?
nasty-shy [4]
-5abc+10d will be the answer.
8 0
2 years ago
Read 2 more answers
Vertex A in quadrilateral ABCD lies at (-3, 2). If you rotate ABCD 180° clockwise about the origin, what will be the coordinates
Marysya12 [62]
I think it might be B hope I’m right
3 0
2 years ago
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A toddler is allowed to dress himself on Mondays, Wednesdays, and Fridays. For each of his shirt, pants, and shoes, he is equall
avanturin [10]

Answer:

0.0286 = 2.86% probability that today is Monday.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Dressed correctly

Event B: Monday

Probability of being dressed correctly:

100% = 1 out of 4/7(mom dresses).

(0.5)^3 = 0.125 out of 3/7(toddler dresses himself). So

P(A) = 0.125\frac{3}{7} + \frac{4}{7} = \frac{0.125*3 + 4}{7} = \frac{4.375}{7} = 0.625

Probability of being dressed correctly and being Monday:

The toddler dresses himself on Monday, so (0.5)^3 = 0.125 probability of him being dressed correctly, 1/7 probability of being Monday, so:

P(A \cap B) = 0.125\frac{1}{7} = 0.0179

What is the probability that today is Monday?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0179}{0.625} = 0.0286

0.0286 = 2.86% probability that today is Monday.

4 0
2 years ago
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