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ra1l [238]
2 years ago
9

A freight carrier charges $0.57 for a package weighing up to one ounce plus and additional $0.32 for each additional ounce or fr

action of an ounce. A company is shipping a package weighing 224 grams. What is the cost to ship the package in dollars and cents?
Mathematics
1 answer:
kherson [118]2 years ago
3 0

We have to write an equation that uses this info so we can find the cost to ship that package. However, the package weight is given to us in grams and we need it in ounces. So first thing we are going to do is convert that 224 g to ounces. Use the fact that 1 g = .035274 ounces to convert. 224g*\frac{.035274oz}{1g}. Do the multiplication and cancel out the label of grams and we have 7.901376 ounces. Ok. We know that it costs .57 to mail the package for the first ounce. We have almost 8 ounces. So no matter what, we are paying .57. For each additional ounce we are paying .32. The number of .32's we have to spend depends upon how much the package goes over the first ounce. For the first ounce we pay .57, then for the remaining 6.901376 ounces we pay .32 per ounce. Our equation looks like this: C(x) = .32(6.901376) + .57 and we need to solve for the cost, C(x). Doing the multiplication we find that it would cost $2.78 to ship that package.

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Joaquin and Trisha are playing a game in which the lower median wins the game. Their scores are shown below.
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Median is defined as the middle term when the scores are arranged in increasing/decreasing order.

Joaquin's scores: 58, 62, 72, 75, 85, 91        Median: 73.5
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The answer is letter A. 
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Aisha is playing a game in which she can gain or lose points on each turn. The table below
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Step-by-step explanation:

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Among all monthly bills from a certain credit card company, the mean amount billed was $465 and the standard deviation was $300.
Fynjy0 [20]

Answer:

0.02% probability that the average amount billed on the sample bills is greater than $500.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 465, \sigma = 300, n = 900, s = \frac{300}{\sqrt{900}} = 10.

What is the probability that the average amount billed on the sample bills is greater than $500?

This probability is 1 subtracted by the pvalue of Z when X = 500. So

Z = \frac{X - \mu}{s}

Z = \frac{500 - 465}{10}

Z = 3.5

Z = 3.5 has a pvalue of 0.9998.

So there is a 1-0.9998 = 0.0002 = 0.02% probability that the average amount billed on the sample bills is greater than $500.

8 0
2 years ago
Alex can ski 960 meters in 5 minutes. If his skiing speed is increased by 20 m/min, how many meters can he cover in 10 minutes?
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First let's find out how much he can ski per minute without his increase in speed.
To find speed we will have to divide distance by time.
960÷5=232
So his speed is 232 meters per second.
Now to this as add 20.
232+20=252
Then to find out how far he will go in 10 minutes,we will just have to multiply 252 by 10
252×10=2520
So your answer will be that Alex will go 2520 meters in 10 minutes.
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