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In-s [12.5K]
2 years ago
15

Which graph could represent a car that begins by increasing its speed, then travels at a constant speed, and then decreases its

speed, as time increases?

Mathematics
2 answers:
Savatey [412]2 years ago
8 0
The graph would almost look like this

Vilka [71]2 years ago
8 0

Which graph could represent a car that begins by increasing its speed, then travels at a constant speed, and then decreases its speed, as time increases?




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Which expression is equivalent to 7a2b + 10a2b2 + 14a2b3?
Ugo [173]
The given expression can be simplified in many ways by grouping like terms. The simplest form is obtained by factoring out a²b which gives us the following expression.

a²b(7 + 10b +14b²)
4 0
2 years ago
Read 2 more answers
An unloaded truck and trailer, with the driver aboard, weighs 30{,}00030,00030, comma, 000 pounds. When fully loaded, the truck
kari74 [83]

Answer:

1131 pounds.

Step-by-step explanation:

We have been given that an unloaded truck and trailer, with the driver aboard, weighs 30,000 pounds. When fully loaded, the truck holds 26 pallets of cargo, and each of the 18 tires of the fully loaded semi-truck bears approximately 3,300 pounds.

First of all, we will find weight of 18 tires by multiplying 18 by 3,300 as:

\text{Weight of tires of the fully loaded semi-truck}=18\times 3,300

\text{Weight of tires of the fully loaded semi-truck}=59,400

The weight of 26 pallets would be weight of 18 tires minus weight of unloaded truck.

\text{Weight of 26 pallets of cargo}=59,400-30,000

\text{Weight of 26 pallets of cargo}=29,400

Now, we will divide 29,400 by 26 to find average weight of one pallet of cargo.

\text{Average weight of one pallet of cargo}=\frac{29,400}{26}

\text{Average weight of one pallet of cargo}=1130.769230769

\text{Average weight of one pallet of cargo}\approx 1131

Therefore, the average weight of one pallet of cargo is approximately 1131 pounds.

3 0
2 years ago
Name two ways you might see decimals used outside of school.
slega [8]
In money and weighing things 
7 0
2 years ago
Read 2 more answers
For ΔABC, ∠A = 4x - 10, ∠B = 5x + 10, and ∠C = 7x + 20. If ΔABC undergoes a dilation by a scale factor of 1 3 to create ΔA'B'C'
VLD [36.1K]
We know that the angles of a triangle sum to 180°.  For ΔABC, this means we have:
(4x-10)+(5x+10)+(7x+20)=180

Combining like terms,
16x+20=180

Subtracting 20 from both sides:
16x=160

Dividing both sides by 16:
x=10
This means ∠A=4*10-10=40-10=30°; ∠B=5*10+10=50+10=60°; and ∠C=7*10+20=70+20=90.

For ΔA'B'C', we have
(2x+10)+(8x-20)+(10x-10)=180

Combining like terms, 
20x-20=180

Adding 20 to both sides:
20x=200

Dividing both sides by 20:
x=10

This gives us ∠A'=2*10+10=20+10=30°; ∠B'=8*10-20=80-20=60°; and ∠C'=10*10-10=100-10=90°.

Since the angle are all congruent, ΔABC~ΔA'B'C' by AAA.
5 0
2 years ago
Read 2 more answers
a museum employee surveys a random sample of 350 visitors to the museum. Of those visitors, 266 stopped at the gift shop. Based
Naddika [18.5K]

1748 people are expected to stop at the gift shop out of 2300.

Step-by-step explanation:

Given,

Number of random sampled people = 350

Number of people who stopped at shop = 266

Percentage = \frac{People\ stopped}{Total\ people}*100

Percentage = \frac{266}{350}*100=76\%

Therefore,

76% people would stop at the gift stop.

Number of people = 2300

Expected number = 76% of total

Expected number = \frac{76}{100}*2300

Expected number = 1748

1748 people are expected to stop at the gift shop out of 2300.

4 0
2 years ago
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