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In-s [12.5K]
1 year ago
15

Which graph could represent a car that begins by increasing its speed, then travels at a constant speed, and then decreases its

speed, as time increases?

Mathematics
2 answers:
Savatey [412]1 year ago
8 0
The graph would almost look like this

Vilka [71]1 year ago
8 0

Which graph could represent a car that begins by increasing its speed, then travels at a constant speed, and then decreases its speed, as time increases?




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Select from the drop-down menus to correctly complete the statements about the expression d3+4e .
-Dominant- [34]

Answer: Hey there! Here are the answers to your question.

Step-by-step explanation:

1. D3+4E is a...

A. Sum

--------------------

2. D3 is also a...

A. Quotient.

---------------------

4E is also a...

A. Product.

If I got any answers wrong, I'm really sorry for my mistakes.

Good luck and I hope this help you out!

8 0
1 year ago
Read 2 more answers
During a catered lunch, an average of 4 cups of tea are poured per minute. The lunch will last 2 hours. How many gallons of tea
EastWind [94]
<span> 4 cups of tea are poured per minute
2 hours = 2 x 60 = 120 minutes
so in 2 hours = 120 x 4 = 480 cups
</span><span>16 cups in one gallon then
</span><span>480 / 16 = 30 gallons

answer
30 gallons


</span>
5 0
1 year ago
Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =
FromTheMoon [43]

Answer:

Here is the question attached with.

m\angle CEA =90 \ (deg)

m\angle BEF=135\ (deg)

\angle CEF is a straight line.

\angle AEF is a right angled triangle.

Options 1,4,5,6 are correct answers.

Step-by-step explanation:

⇒As \ ray\ AE  is ⊥FEC so it will forms right angled triangle then m\angle CEA =90\ (deg).

⇒Measure of \angle BEF =135\ (deg) as \angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg) as \angle AEB is the bisector of \angle AEC,meaning that  \angle AEB is half of \angle AEC so  \angle AEB = 45\ (deg).

⇒\angle CEF is a straight line as the angles measure over it is 180\ (deg).

⇒Measure of \angle AEF = 90\ (deg) from linear pair concept.

As \angle CEA + \angle AEF = 180\ (deg),plugging the values of  m\angle CEA =90\ (deg) we have \angle AEF = 90\ (deg) .

The other two options are false as:

  • m\angle CEF=m\angle CEA + m\angle BEF = (90+135)=225

       it is exceeding 180\ (deg) whereas \angle CEF is a              

      straight line.

  • And m\angle CEB=2(m\angle CEA) is not true.

     As \angle CEA = 90\ (deg) and \angle CEB=45\ (deg)

So we have total 4 answers.

The correct options are 1,4,5,6.

5 0
2 years ago
Read 2 more answers
Nevin made tables of values to approximate the solution to a system of equations. First he found that the x-value of the solutio
prisoha [69]

Answer:

The correct option is B.

Step-by-step explanation:

The given equation are

y=4x-3

y=-5x+9

On solving both the equation, we get

4x-3=-5x+9

4x+5x=9+3

9x=12

9x=\frac{12}{9}=\frac{4}{3}

Put this value in the given equation.

y=4(\frac{4}{3})-3

y=\frac{16}{3}-3

y=\frac{16-9}{3}

y=\frac{7}{3}

The solution of the given system of equation is

(\frac{4}{3},\frac{7}{3})=(1.333,2.333)\approx (1.3,2.3)

The best approximation of the exact solution is (1.3,2.3). Therefore the correct option is B.

7 0
2 years ago
Read 2 more answers
Mrs. Ronilo had her students make a stem-and-leaf plot of the heights of all of the students in the class. The mean was 55. Dave
shutvik [7]
Given that the mean is 55 inches  and Dave is 57 inches, he would have increased the mean of the height in the stem-and-leaf plot that the students were making. This is however is also dependent upon the central tendency that was used, in this case the central tendency is mean or average. 
8 0
1 year ago
Read 2 more answers
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