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1 year ago

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44 students completed some homework and the histogram shows information about the times taken. Work out an estimate of the inter

quartile range. In your working you must show the lower and upper quaratiles

1 answer:

Vilka [71]1 year ago

5 0

Answer:

q1=11

q3= 33

Step-by-step explanation:

The data set has 44 number of students. The first quartile is 25 % of the numbers in the data set . So

25 % of 44 = 25/100 * 44= 0.25 *44 = 11

So the first quartile lies at 11.

Similarly the third quartile lies at the 75 % of the numbers of the data set . So

75 % of 44 = 75/100 * 44= 0.75 *44 = 33

So the third quartile lies at 33.

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Janie ordered boxed lunches for a student advisory committee meeting. Each lunch costs $4.25. The total cost of the lunches is $

andriy [413]

Answer:

11 boxed lunches

Step-by-step explanation:

Full question

Janie ordered boxed lunches for a student advisory committee meeting. Each lunch cost 4.25. The total cost of the lunches is 53.75, including a 7$ delivery fee. Write and solve an equation to find x the number of boxed lunches Janie ordered

First of all subtract the delivery feesince it was inckuded in the total cost, this will now be the total cost of all the noxed lunches ordered by Janie, then divide the balance of the total cost by the cost of one boxed lunch to get thd total boxed kunches

X= 53.75-7/4.25

X= 53.75-7= 46.75/4.25

X=11

7 0

1 year ago

Read 2 more answers

7700 dollars is placed in an account with an annual interest rate of 5.75%. How much will be in the account after 24 years, to t

Amanda [17]

Answer:

A = $18,326.00

(assuming simple interest)

Step-by-step explanation:

Assuming simple interest, the following formula applies:

final amount = (principal amount) x [1 + (annual rate)(time elapsed) ]

or

A = P (1 + rt)

in our case,

P = $7,700

r = 5.75% = 0.0575

t = 24 years

hence,

A = 7700 [ 1 + (0.0575)(24)]

A = 7700 ( 1 + 1.38)

A = 7700 x 2.38

A = $18,326.00

4 0

1 year ago

Rectangle ABCD was dilated to create rectangle A'B'C'D' using point R as the center of dilation.

Slav-nsk [51]

Answer:

5

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.Tiles

Ugo [173]

By definition, the average rate of change is given by:

$AVR = \frac{f(x2)-f(x1)}{x2-x1}$

We evaluate each of the functions in the given interval.

We have then:

For f (x) = x ^ 2 + 3x:

Evaluating for x = -2:

$f (-2) = (-2) ^ 2 + 3 (-2)\\f (-2) = 4 - 6\\f (-2) = - 2$

Evaluating for x = 3:

$f (3) = (3) ^ 2 + 3 (3)\\f (3) = 9 + 9\\f (3) = 18$

Then, the AVR is:

$AVR = \frac{18-(-2)}{3-(-2)}$

$AVR = \frac{18+2}{3+2}$

$AVR = \frac{20}{5}$

$AVR = 4$

For f (x) = 3x - 8:

Evaluating for x =4:

$f (4) = 3 (4) - 8\\f (4) = 12 - 8\\f (4) = 4$

Evaluating for x = 5:

$f (5) = 3 (5) - 8\\f (5) = 15 - 8\\f (5) = 7$

Then, the AVR is:

$AVR = \frac{7-4}{5-4}$

$AVR = \frac{3}{1}$

$AVR = 3$

For f (x) = x ^ 2 - 2x:

Evaluating for x = -3:

$f (-3) = (-3) ^ 2 - 2 (-3)\\f (-3) = 9 + 6\\f (-3) = 15$

Evaluating for x = 4:

$f (4) = (4) ^ 2 - 2 (4)\\f (4) = 16 - 8\\f (4) = 8$

Then, the AVR is:

$AVR = \frac{8-15}{4-(-3)}$

$AVR = \frac{-7}{4+3}$

$AVR = \frac{-7}{7}$

$AVR = -1$

For f (x) = x ^ 2 - 5:

Evaluating for x = -1:

$f (-1) = (-1) ^ 2 - 5\\f (-1) = 1 - 5\\f (-1) = - 4$

Evaluating for x = 1:

$f (1) = (1) ^ 2 - 5\\f (1) = 1 - 5\\f (1) = - 4$

Then, the AVR is:

$AVR = \frac{-4-(-4)}{1-(-1)}$

$AVR = \frac{-4+4}{1+1}$

$AVR = \frac{0}{2}$

$AVR = 0$

Answer:

from the greatest to the least value based on the average rate of change in the specified interval:

f(x) = x^2 + 3x interval: [-2, 3]

f(x) = 3x - 8 interval: [4, 5]

f(x) = x^2 - 5 interval: [-1, 1]

f(x) = x^2 - 2x interval: [-3, 4]

4 0

1 year ago

Becky is buying fabric to make new pillows for her couch. She spends $71.50 on striped fabric and $52.25 on checkered fabric. If

Gnom [1K]

Answer:

i think you add both fabric prices then divide with 5.50

7 0

1 year ago