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Dafna11 [192]
2 years ago
5

Mr. Peter charges $2.25 for the usage of laptop for 9 hours. How much Victor needs to pay for 15 hours of usage?

Mathematics
2 answers:
gregori [183]2 years ago
8 0

Answer:

$6.00

Step-by-step explanation:

Well, 2.25 for every 9hrs so we can divide 9 by 2.25 and we will get 40 cents an hour. So 40x15= $6.00

hope im right

Papessa [141]2 years ago
5 0

Answer:

3.75

Step-by-step explanation:

2.25 divided by 9

= 0.25

then

0.25 * 9

= 3.75

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It takes 48 pounds of seeds to completely plant a five acre field, how many acres can be planted per pound?
lana [24]

Answer:

9.6

Step-by-step explanation:

So you divide 48 Divided by 5 wich equals 9.6 HOPE THIS HELPS

4 0
2 years ago
Lisa is william's niece, but she isn't emily niece even though emily is williams sister and william not married. how is it possi
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Is she the family member on the others family side or is it like harder
6 0
2 years ago
Which inequality is true if p= 3.4?
BigorU [14]

Answer:

None of the equations are true for p = 3.4

Step-by-step explanation:

In order for the inequality to be valid we need to apply the value for p and check wether or not it is true. We gonna do for each of the following:

A. 3p < 10.2

3*3.4 < 10.2

10.2 < 10.2

Not true, since the left side is equal to the right side and not less.

B. 13.6 < 3.9p

13.6 < 3.9*3.4

13.6 < 13.26

Not true since 13.6 is greater than 13.26

C. 5p > 17.1

5*3.4 > 17.1

17 > 17.1

Not true since 17 is less than 17.1

D. 8.5 > 2.5p

8.5 > 2.5*3.4

8.5 > 8.5

Not true since the left side is equal to the right side.

7 0
2 years ago
Suppose that the IQs of university​ A's students can be described by a normal model with mean 140 and standard deviation 8 poi
AnnZ [28]

Answer:

0.0266, 0.9997,0.7856

Step-by-step explanation:

Given that the IQs of university​ A's students can be described by a normal model with mean 140 and standard deviation 8 points. Also suppose that IQs of students from university B can be described by a normal model with mean 120 and standard deviation 11. Let x be the score by A students and Y the score of B.

A)P(X>135) = \\P(Z>0.625)\\=0.0266

B) Since X and Y are independent we have

X-Y is Normal with mean = 140-120 =20 and Var (x-y)=Var(x)+Var(y) = 19

P(X-Y)>5\\\\=1-0.00029\\=0.9997

C) For a group of 3, average has std deviation = \frac{11}{\sqrt{3} } \\=6.351

P(\bar y >115)\\= P(z>\frac{-5}{6.351} \\=0.7856

3 0
2 years ago
A club is making posters to raise money. The printing company charges a base fee of $60 and $2 per poster. How many posters can
Ad libitum [116K]

Answer:

120 posters

Step-by-step explanation:

300 - 60 = 240

240/2 = 120

8 0
2 years ago
Read 2 more answers
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