You are given two points on a line, and told that the function is "direct variation." You can save a lot of time by recognizing that the y-intercept here is zero (0). Thus, the line passes through the origin.
A line through (2,14) and (4,38) is NOT direct variation, because the line connecting those two points does NOT pass through the origin, and thus has a vertical intercept.
Answer:
The correct options are 1 and 3.
Step-by-step explanation:
From the given box plot it is clear that


Q₁ is 25% of a data.

Median is 50% of a data.

Q₃ is 75% of a data.

34 is minimum value of the data and 46 is median it means 50% of the data values lies between 34 and 46. Therefore option 1 is correct.
42 is first quartile and and 70 is third quartile. it means 50% of the data values lies between 42 and 70. Therefore option 2 is incorrect.
The difference between Minimum value and first quartile, Maximum value and third quartile is less than 1.5×(IQR), therefore it is unlikely to have any outliers in the data.
Hence option 3 is correct.
The interquartile range of the data is


The interquartile range is 28. Therefore option 4 is incorrect.
Range of the data is


The range is 42. Therefore option 5 is incorrect.
Answer:
If the limit that you want to find is
then you can use the following proof.
Step-by-step explanation:
Let
and
be the given polinomials. Then

Observe that

and

Then

Answer:
b
Step-by-step explanation:
25 minutes
So the given series is "16, 06, 68, 88, __"
Count all the cyclical opening in each of these numbers. For example in 16, there is a one cyclical loop present in it(the one in 6), similarly in 06 it is two(one in zero and one in 6), going ahead, in 68 it is 3(one in 6 and two in 8).
From here on things become simple: hence, the cyclical figures in these equations written down becomes 1,2,3,4,_,3.
Let's now try solving the above sequence, going by the logical reasoning the only number that can fill in the gap should be 4.