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polet [3.4K]
2 years ago
10

A race car driver lost 8 seconds off the leader for each of the 3 pit stops the driver made. At each of the next 2 pit stops the

driver gained 10 seconds on the leader. Which represents the amount of time the driver is off the leader? A. –4 secondsB. –2 seconds C.20 seconds D.54 seconds ASAP
Mathematics
2 answers:
LiRa [457]2 years ago
8 0
The answer would be A.
if he lost 8 seconds off of 3 pit stops that means he lost 24 seconds. if he can’t 10 seconds for the 2 he made, he gained 20. so therefore, he is only 4 seconds behind the leader. I hope this helps :)
BlackZzzverrR [31]2 years ago
7 0

Answer:

The answer is A

Step-by-step explanation:

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Step-by-step explanation:

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A Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer; a sample
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Answer:

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given first random sample size n₁ = 500</em>

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<em>First sample proportion </em>

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<em>Given second sample size n₂ = 700</em>

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<em>Level of significance = α = 0.05</em>

<em>critical value = 1.96</em>

<u><em>Step(ii)</em></u><em>:-</em>

<em>Null hypothesis : H₀: There  is no significance difference between these proportions</em>

<em>Alternative Hypothesis :H₁: There  is significance difference between these proportions</em>

<em>Test statistic </em>

<em></em>Z = \frac{p_{1} ^{-}-p^{-} _{2}  }{\sqrt{PQ(\frac{1}{n_{1} } +\frac{1}{n_{2} } )} }<em></em>

<em>where </em>

<em>         </em>P = \frac{n_{1} p^{-} _{1}+n_{2} p^{-} _{2}  }{n_{1}+ n_{2}  } = \frac{500 X 0.13+700 X0.19  }{500 + 700 } = 0.165<em></em>

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<em>There is there is a difference between these proportions at α = 0.05</em>

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Answer/Step-by-step explanation:

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