Answer:
1. <u>$14.88</u>
2. <u>$12.40</u>
Step-by-step explanation:
An english translation:
<em>A company transports office cabinets to a location 425km away. Its cost is R $ 2.10 per km traveled. When the cabinets are assembled, the vehicle's capacity is 60 units. When they are disassembled the capacity increases 6 times. We ask: 1- What is the cost per assembled cabinet? 2- What is the savings per cabinet, when these are taken apart.</em>
<em />
<u>Solution:</u>
425 km with 2.10 per km means:
425 * 2.10 = $892.50 total cost
Now, when assembled, there goes 60 cabinets, so cost per assembled cabinet is:
<u>Cost per assembled cabinet = 892.5/60 = $14.875 = $14.88</u>
<u></u>
The capacity of 60 after disembling, it becomes:
60 * 6 = 360
So, cost per cabinet becomes:
892.5/360 = <u>$2.48</u>
The savings is how much you save up if they were assembled:
14.88 - 2.48 = <u>$12.40</u>
<u>Savings = $12.40</u>
Answer:
32, 37, 42, 47, 52, 57, 62.
Step-by-step explanation:
It is given that Carissa counts by 5s from 32 to 62.
It means, we have to add 5 in the number to get the next number.
Add 5 in 32.

Now, add 5 in 37.

Similarly, continue the process.




Therefore, the numbers counted by carissa are 32, 37, 42, 47, 52, 57, 62.
Answer:
∅1=15°,∅2=75°,∅3=105°,∅4=165°,∅5=195°,∅6=255°,∅7=285°,
∅8=345°
Step-by-step explanation:
Data
r = 8 sin(2θ), r = 4 and r=4
iqualiting; 8.sin(2∅)=4; sin(2∅)=1/2, 2∅=asin(1/2), 2∅=30°, ∅=15°
according the graph 2, the cut points are:
I quadrant:
0+15° = 15°
90°-15°=75°
II quadrant:
90°+15°=105°
180°-15°=165°
III quadrant:
180°+15°=195°
270°-15°=255°
IV quadrant:
270°+15°=285°
360°-15°=345°
No intersection whit the pole (0)
Answer:
A. There are not 15 successes and 15 failures. A confidence interval can be computed by adding 2 successes and 2 failures.