Answer:
It is C -14r+6p
Step-by-step explanation:
If you want the explanation just tell me
<em><u>Two</u></em> of the four statements that Ana wrote are <em><u>correct</u></em>. Number 1, "AB is a diameter" is incorrect, and so is number 3, "SQ = 12 cm". AB is not a diameter because it is instead a chord. "ST , SP and SQ are radii" is correct because they are straight lines from the center of the circle to the circumference of the circle, which is the exact definition of radius. The third statemet is incorrect because since ST is a radius and it equals 6, that means all radii are equal to 6. SQ is a radius of circle S, so it should also equal 6, not 12. The last statement is correct because PQ is a diameter of circle S. By rule, the diameter is always equal to double of the radius. The radius is 6, so 6 x 2= 12.
We have the expression:
3x(x-12x) + 3x^2 - 2(x-2)^2
First, we will expand the power 2 bracket as follows:
3x(x-12x) + 3x^2 - 2(x^2 - 4x +4)
Then, we will get rid of the brackets as follows:
3x^2 - 36x^2 + 3x^2 - 2x^2 + 8x - 8
Now, we will gather the like terms and add them as follows:
-32 x^2 + 8x - 8
We can take the 8 as a common factor:
8 ( -4x^2 + x -1)
4(2 - x) > -2x - 3(4x + 1)
8 - 4x > -2x - 12x - 3
-4x + 2x + 12x > -3 - 8
10x > -11
x > -11/10
x > -1.1
Therefore, x = 0 and x = 10 zre solutions to the inequality.
