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mina [271]
2 years ago
6

Explain when the median of a data set is a better measure of center than the mean

Mathematics
2 answers:
choli [55]2 years ago
7 0

Answer:

Sample Response: When there is an outlier in the data set, the dot plot or histogram will be skewed. In a skewed representation, the mean is pulled up or down toward the tail of the data. Therefore, skewed data affects the mean more than the median.

What did you include in your response? Check all that apply.

The dot plot or histogram will be skewed.

The mean is pulled up or down toward the tail.

The mean is affected more than the median.

vlada-n [284]2 years ago
5 0

The dot plot or histogram will be skewed.

The mean is pulled up or down toward the tail.

The mean is affected more than the median.


Sample Response: When there is an outlier in the data set, the dot plot or histogram will be skewed. In a skewed representation, the mean is pulled up or down toward the tail of the data. Therefore, skewed data affects the mean more than the median.

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That whole eqation is 40
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Which point is a solution of x + 2y ≤ 4?
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The erea of a square is given by x2, where x is the length of one side. Mary's original garden was in the shape of a square. She
crimeas [40]

Answer: The expression that represents the area of Mary's new garden =2x^2

Step-by-step explanation:

The area of a square is given by x^2, where x is the length of one side. The length of the other side is also x. In a square, all sides are equal. each of the four sides equal x

Area = x × x

Area = x^2

She decided to double the area of her garden

New area = 2(x × x)

New area = 2x^2

The expression that represents the area of Mary's new garden =2x^2

7 0
2 years ago
a previous analysis of paper boxes showed that the standard deviation of their lengths is 15 millimeters. A packers wishes to fi
vladimir1956 [14]

Answer:

864.36 boxes

Step-by-step explanation:

In the question above, we are given the following values,

Confidence interval 95%

Since we know the confidence interval, we can find the score.

Z score = 1.96

σ , Standards deviation = 15mm

Margin of error = 1 mm

The formula to use to solve the above question is given as:

No of boxes =[ (z score × standard deviation)/ margin of error]²

No of boxes = [(1.96 × 15)/1]²

= 864.36 boxes

Based on the options above, we can round it up to 97 boxes.

8 0
2 years ago
Consider the polynomial: StartFraction x Over 4 EndFraction – 2x5 + StartFraction x cubed Over 2 EndFraction + 1 Which polynomia
Phoenix [80]

Answer:

- 2x^5+ 0x^4 +  \frac{x^3}{2} +0x^2+\frac{x}{4}  + 1

Step-by-step explanation:

Given

\frac{x}{4} - 2x^5 + \frac{x^3}{2} + 1

Required

The standard form of the polynomial

The general form of a polynomial is

ax^n + bx^{n-1} + cx^{n-2} +........+ k

Where k is a constant and the terms are arranged from biggest to smallest exponents

We start by rearranging the given polynomial

- 2x^5+ \frac{x^3}{2} +\frac{x}{4}  + 1

Given that the highest exponent of x is 5;

Let n = 5

Then we fix in the missing terms in terms of n

- 2x^5+ 0x^{n-1} +  \frac{x^3}{2} +0x^{n-3}+\frac{x}{4}  + 1

Substitute 5 for n

- 2x^5+ 0x^{5-1} +  \frac{x^3}{2} +0x^{5-3}+\frac{x}{4}  + 1

- 2x^5+ 0x^{4} +  \frac{x^3}{2} +0x^{2}+\frac{x}{4}  + 1

Hence, the standard form of the given polynomial is - 2x^5+ 0x^4 +  \frac{x^3}{2} +0x^2+\frac{x}{4}  + 1

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2 years ago
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