Which shows the following expression after the negative exponents have been eliminated?

On a coordinate plane, point C has coordinates of (-8, -15) and point D has coordinates of (9, -3). What are the coordinates of

Anna [14]

Answer: H

Step-by-step explanation:

4 0

1 year ago

On a coordinate plane, a circle has a center at (negative 2, 0). Point (negative 2, 4) lies on the circle. Distance formula: Sta

vivado [14]

Answer:

its B on Ed

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

13. En un pueblo, 5 personas escucharon una noticia. En una hora, cada una de ellas

Vera_Pavlovna [14]

Answer:

En 5 horas se habrá enterado todo el pueblo.

Step-by-step explanation:

Sabemos que en un pueblo 5 personas escucharon una noticia.

Una hora más tarde, cada una de ellas le contó la noticia a otras 5.

Luego, éstas contaron la noticia a otras 5 y así sucesivamente.

Nadie cuenta ni escucha la noticia más de una vez y en ese pueblo hay un poco más de 19000 habitantes.

La ecuación a desarrollar para resolver el problema es la siguiente :

Comenzamos con 5 personas que escucharon la noticia a la ''hora 0''.

Una hora más tarde, cada una de ellas le contó a 5 personas, es decir , pasada la primera hora tendremos :

$5+5^{2}=30$ (I)

Las 5 personas originales de la ''hora 0'' más 25 personas que se enteraron pasada la primera hora. La ecuación que planteamos es la siguiente :

$5^{1}+5^{2}+5^{3}+...+5^{x}>19000$ (II)

Buscamos el valor de $x$ que satisface la ecuación (II).

Probando y realizando las sumas encontramos que :

$5^{1}+5^{2}+5^{3}+5^{4}+5^{5}+5^{6}>19000$

$19530>19000$

El valor de $x$ que satisface (II) es $x=6$ .

Para hallar el número de horas nos fijamos que en (I) el valor del mayor exponente del 5 es el número 2. Para ese valor 2, el tiempo que pasó es una hora.

Entonces para nuestro $x=6$ , el número de horas que pasaron son 5 horas (1 menos que el valor de $x$ )

Todo el pueblo se habrá enterado en 5 horas de la noticia.

7 0

2 years ago

Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The

abruzzese [7]

The question is incorrect.

The correct question is:

Three TAs are grading a final exam.

There are a total of 60 exams to grade.

(c) Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The TAs grade at different rates, so the first TA will grade 25 exams, the second TA will grade 20 exams and the third TA will grade 15 exams. How many ways are there to distribute the exams?

Answer: 60!/(25!20!15!)

Step-by-step explanation:

The number of ways of arranging n unlike objects in a line is n! that is ‘n factorial’

n! = n × (n – 1) × (n – 2) ×…× 3 × 2 × 1

The number of ways of arranging n objects where p of one type are alike, q of a second type are alike, r of a third type are alike is given as:

n!/p! q! r!

Therefore,

The answer is 60!/25!20!15!

6 0

1 year ago

James and Terry open a savings account that has a 2.75% annual interest rate, compounded monthly. They deposit $500 into the acc

katovenus [111]

Answer:

<h2>Option A is the answer(here the answer is calculated taking the whole value, without approximating it to a nearest value)</h2>

Step-by-step explanation:

Annual interest rate is 2.75%. Hence, the monthly interest rate is $\frac{2.75}{12}$

The amount will be compounded $(20\times12) = 240$ times.

Every month they deposits $500.

In the first month that deposited $500 will be compounded 240 times.

It will be $500\times [1 + \frac{2.75}{1200} ]^{240}$

In the second month $500 will be deposited again, this time it will be compounded 239 times.

It will give $500\times [1 + \frac{2.75}{1200} ]^{239}$

Hence, the total after 20 years will be $500\times [1 + \frac{2.75}{1200} ]^{240} + 500\times [1 + \frac{2.75}{1200} ]^{239} + ........+ 500\times [1 + \frac{2.75}{1200} ]^{1} = 160110.6741$

7 0

2 years ago