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Alika [10]
2 years ago
12

F(x)=x2−x−1f, left parenthesis, x, right parenthesis, equals, x, squared, minus, x, minus, 1 What is the average rate of change

of fffover the interval -1\leq x\leq 1−1≤x≤1minus, 1, is less than or equal to, x, is less than or equal to, 1?

Mathematics
1 answer:
Alexandra [31]2 years ago
5 0

Answer: The average rate of change = -1

Step-by-step explanation: Please find the attached file for the solution

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Mia has a conical container filled with chocolates. She knows that the volume of the container is equal to one-third of the prod
34kurt
For this case what you should do is create the equation based on:
 "She knows that the volume of the container is equal to one-third of the product, the square of the radius of the base of the container, and the height of the container"
 We have then that the Volume is given by:
 V = (1/3) * (r ^ 2) * (h)
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 h: height of the container.
 answer
 The volume of the container is calculated with the following equation:
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7 0
2 years ago
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Suppose that water is pouring into a swimming pool in the shape of a right circular cylinder at a constant rate of 8 cubic feet
adell [148]

Answer:

dh/dt = 0,07 ft/min

Step-by-step explanation:

The swimming pool has the shape of right circular cylinder, therefore its volume is

V(c) = π*x²*h

Where x is the radius of the base and h the height

We take differentiation on both sides of the equation to get:

dV/dt  =  π*x²*dh/dt

The rate of change in height of water in the pool, is independent of the height of the water, since the pool is a right crcular cylinder, and dV/dt is constant at 8 ft³/min.

Then:

8  = π*x²*dh/dt

dh/dt = 8 /  π*x²

dh/dt = 8/113,04

dh/dt = 0,07 ft/min

7 0
2 years ago
Express 25.6 nanometres in metres, giving your answer in standard form.​
zhannawk [14.2K]

Answer:

10 to power of -8 so 0.00000001 I think

8 0
2 years ago
Given: Circle X with a Radius r and circle Y with radius s Prove: Circle x is similar to circle y
lana [24]

Two figures are similar if one is the scaled version of the other.

This is always the case for circles, because their geometry is fixed, and you can't modify it in anyway, otherwise it wouldn't be a circle anymore.

To be more precise, you only need two steps to prove that every two circles are similar:

  1. Translate one of the two circles so that they have the same center
  2. Scale the inner circle (for example) unit it has the same radius of the outer one. You can obviously shrink the outer one as well

Now the two circles have the same center and the same radius, and thus they are the same. We just proved that any two circles can be reduced to be the same circle using only translations and scaling, which generate similar shapes.

Recapping, we have:

  1. Start with circle X and radius r
  2. Translate it so that it has the same center as circle Y. This new circle, say X', is similar to the first one, because you only translated it.
  3. Scale the radius of circle X' until it becomes s. This new circle, say X'', is similar to X' because you only scaled it

So, we passed from X to X' to X'', and they are all similar to each other, and in the end we have X''=Y, which ends the proof.

8 0
2 years ago
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The final velocity of an object moving in on one dimension is given by the formula v = u + at, where u is the initial velocity,
agasfer [191]

Answer:

Given Below

Step-by-step explanation:

v = u+at

u+at = v

at = v-u

t = v-u/a

Hope this helps

8 0
2 years ago
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