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2 years ago

Given: FH ⊥ GH; KJ ⊥ GJ Prove: ΔFHG ~ ΔKJG Identify the steps that complete the proof. ♣ = ♦ = ♠ =

2 answers:

6 0

1 is all right angles are congruent 2 angles fgh is congruent to angle kgj 3 aa similarity theorem just took the test this are correct

Elanso [62]2 years ago

5 0

Answer:

All right angles are congruent

Angle FGH is congruent to angle KGJ

AA similarity theorem

Step-by-step explanation:

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Eva has four sets of straws.

hodyreva [135]

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You need to use trigonometry, and square all of the numbers, you then add the lowest two and they should sum to the other number.

The set that this works for is the correct set.

Hope this helps x

8 0

2 years ago

Read 2 more answers

Solve it every process

Naily [24]

g(x) = 2x + 3

f(x) = x^2 + 7

g(f(x)) = 2(x^2 + 7) + 3

g(f(x)) = 2x^2 + 14 + 3

g(f(x)) = 2x^2 + 17

when g(f(x)) = 25 then

2x^2 + 17 = 25

2x^2 - 8 = 0

2(x^2 - 4) = 0

2(x+2)(x-2) = 0

x + 2 = 0; x = -2

x - 2 = 0; x = 2

Answer

x = 2 or - 2

5 0

2 years ago

An experiment was performed to compare the abrasive wear of two different laminated materials. Twelve pieces of material 1 were

vladimir1956 [14]

Answer:

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

There is significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units

Step-by-step explanation:

Step:-(1)

Given data the samples of material 1 gave an average (coded) wear of 85 units with a sample standard deviation of 4

Mean of the first sample x₁⁻ =85

standard deviation of the first sample S₁ = 4

Given data the samples of material 2 gave an average of 81 and a sample standard deviation of 5.

Mean of the first sample x₂⁻ =81

standard deviation of the first sample S₂ = 5

Step :-2

Null hypothesis: H₀: there is no significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Alternative hypothesis :H₁: there is significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Assume the populations to be approximately normal with equal variances.σ₁² =σ₂²

The test statistic

$Z= \frac{x_{1} -x_{2} }{\sqrt{\frac{S^2_{1} }{n_{1} } +\frac{S^2_{2} }{n_{2} } } }$