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arlik [135]
2 years ago
12

Trisha bought a carton of orange juice. She drank 1/3 of the carton on Monday

Mathematics
2 answers:
attashe74 [19]2 years ago
8 0

Answer:

3\4

Step-by-step explanation:

Luden [163]2 years ago
4 0

Answer:

3/4 of the carton has been drank.

Step-by-step explanation:

Given that:

She drank on Monday = 1/3 of carton

She drank on Tuesday = 5/12 of carton

Total fraction drank = 1/3 + 5/12

Taking LCM to make denominators same:

Total fraction drank = 1/3 * 4/4 + 5/12

Total fraction drank = 4/12 + 5/12

Total fraction drank = 9/12

Reducing the obtained answer we get

Total fraction drank = 3/4

So 3/4 of the carton has been drank.

i hope it will help you!

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kow [346]

The height of Radon plant is 6.3 meters

<em><u>Solution:</u></em>

Given that, Allies plant has a height of 6 meters

Radon’s plant grows \frac{3}{10} meters higher

To find: Height of Radon plant

From given information,

Height of Allies plant = 6 meters

Height of radon plant = \frac{3}{10} + Height of Allies plant

Substituting the known value,

\text{ Height of radon plant} = \frac{3}{10} + 6\\\\\text{ Height of radon plant} = \frac{3+60}{10}\\\\\text{ Height of radon plant} = \frac{63}{10}\\\\\text{ Height of radon plant} = 6.3

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2 years ago
Select the correct answer. What is the greatest common factor of this expression? 12m + 18m2 A. 6m B. 6 C. 2m D. 2
ohaa [14]
A. No matter what M is, it will correspond to the squared version of 18m
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ddd [48]

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Step-by-step explanation:

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2 years ago
An urn contains two blue balls (denoted B1 and B2) and three white balls (denoted W1, W2, and W3). One ball is drawn, its color
alekssr [168]

Answer:

(a) Shown below.

(b) The probability that the first ball drawn is blue is 0.40.

(c) The probability that only white balls are drawn is 0.36.

Step-by-step explanation:

The balls in the urn are as follows:

Blue balls: B₁ and B₂

White balls: W₁, W₂ and W₃

It is provided that two balls are drawn from the urn, with replacement, and their color is recorded.

(a)

The possible outcomes of selecting two balls are as follows:

B₁B₁          B₂B₁          W₁B₁          W₂B₁          W₃B₁

B₁B₂         B₂B₂          W₁B₂         W₂B₂          W₃B₂

B₁W₁         B₂W₁         W₁W₁         W₂W₁         W₃W₁

B₁W₂        B₂W₂         W₁W₂        W₂W₂         W₃W₂

B₁W₃        B₂W₃         W₁W₃        W₂W₃         W₃W₃

There are a total of N = 25 possible outcomes.

(b)

The sample space for selecting a blue ball first is:

S = {B₁B₁, B₁B₂, B₁W₁, B₁W₂, B₁W₃, B₂B₁, B₂B₂, B₂W₁, B₂W₂, B₂W₃}

n (S) = 10

Compute the probability that the first ball drawn is blue as follows:

P(\text{First ball is Blue})=\frac{n(S)}{N}=\frac{10}{25}=0.40

Thus, the probability that the first ball drawn is blue is 0.40.

(c)

The sample space for selecting only white balls is:

X = {W₁W₁, W₂W₁, W₃W₁, W₁W₂, W₂W₂, W₃W₂, W₁W₃, W₂W₃, W₃W₃}

n (X) = 9

Compute the probability that only white balls are drawn as follows:

P(\text{Only White balls})=\frac{n(X)}{N}=\frac{9}{25}=0.36

Thus, the probability that only white balls are drawn is 0.36.

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He made an error is step 2

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