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Lady_Fox [76]
1 year ago
7

For a luxury doughnut producer the average selling price is £2. The average variable cost is 40% of the selling price and its fi

xed cost per day is £300. Calculate total costs per day assuming it produces 400 doughnuts per day.
Mathematics
1 answer:
Cerrena [4.2K]1 year ago
6 0

Answer:

620

Step-by-step explanation:

selling 400 doughnuts means selling 800 £ worth of doughnuts. 800 x 0.4 ( to find 40 percent) = 320, + 300 because the the fixed cost = 620. :)

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Suppose that you want to estimate average income in a population. If the standard deviation of income in the population is $1,00
Alik [6]

Answer:

2401

Step-by-step explanation:

Given that we want to estimate average income in a population.

The standard deviation of income in the population is $1,000

We want confidence interval around our estimate to be +/- $40

i.e Margin of error = 40

We know that margin of error = Std error * Z critical for 95%

i.e. 40 = 1.96 * std error

Std error = \frac{std dev}{\sqrt{n} } \\=\frac{1000}{\sqrt{n} }

Together we get

40=1.96(\frac{1000}{\sqrt{n} } )\\\sqrt{n} =\frac{1000*1.96}{40} \\=49\\n=2401\\

3 0
1 year ago
Please answer this I really need help, Ariel spent a total of $3.42 buying dried apricots from the bulk bins, which were on sale
Kamila [148]

Answer:

1.2 lbs

Step-by-step explanation:

This problem is set up so that the total price is proportional to the price per pound, so to find the proportion you would divide the total cost by the cost per pound. 3.42/2.85 = 1.2, so the answer is 1.2 pounds.

5 0
1 year ago
At the beginning of year 1, paolo invests $500
suter [353]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$500\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annuall, thus once}
\end{array}\to &1\\
t=years\to &t
\end{cases}
\\\\\\
A=500\left(1+\frac{0.04}{1}\right)^{1\cdot t}\implies A=500(1+0.04)^t
\\\\\\
\textit{after 5 years }t=5\qquad A=500(1.04)^5

the example on your picture uses A(n) and n = years, but is pretty much the same, in this case is t = years.
3 0
1 year ago
Read 2 more answers
Xavier is working two summer jobs, making $14 per hour lifeguarding and $15 per hour tutoring. Xavier must earn at least $170 th
Julli [10]

Answer:

Step-by-step explanation:

8 0
2 years ago
Find the average value of the function f(x, y, z) = 5x2z 5y2z over the region enclosed by the paraboloid z = 4 − x2 − y2 and the
S_A_V [24]
The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin. 

<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>

<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>

<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>

<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>


<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>

<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>

<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>

<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>

<span>∴ F = 10935π/8 ÷ 81π/2 = 135/4</span>
3 0
2 years ago
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