Ask question

Ask question

All categories

2 years ago

6

En un campamento de refugiados, cada refugiado recibe la misma ración de comida si se van a repartir 162 paquetes de galletas 32

4 paquetes de arroz y 243 botellas de agua ¿Cuantos refugiados hay en el campamento?

1 answer:

natali 33 [55]2 years ago

8 0

Hay 162 refugiados en el campamento. Si hubiera mas de 162, ya no recivirian la misma racion de comida. Cada uno recive un paquete de galletas, dos paquetes de arroz y pienso k una botella y media de agua (aunque lo de el agua suene un poko ilogico).

You might be interested in

A recent study found that 51 children who watched a commercial for Walker Crisps (potato chips) featuring a long-standing sports

hichkok12 [17]

Answer:

1

The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

2

The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population

3

$t = 3.054$

4

The p-value is $p-value = P(Z > 3.054) = 0.0011291$

5

The conclusion is

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The test statistics is

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 51$

The first sample mean is $\mu_1 = 36$

The second sample size is $n_2 = 41$

The second sample size is $\mu_2 = 25$

The first standard deviation is $\sigma _1 = 21.4 \ g$

The second standard deviation is $\sigma _2 = 12.8 \ g$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o : \mu_1 = \mu_ 2$

The alternative hypothesis is $H_a : \mu_1 > \mu_2$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \= x_2}{ \sqrt{ \frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} } }$

=> $t = \frac{ 36 - 25}{ \sqrt{ \frac{ 21.4^2}{51} + \frac{ 12.8^2}{41} } }$

=> $t = 3.054$

The p-value is mathematically represented as

$p-value = P(Z > 3.054)$

Generally from the z table

$P(Z > 3.054) = 0.0011291$

=> $p-value = P(Z > 3.054) = 0.0011291$

From the values obtained we see that $p-value < \alpha$ so the null hypothesis is rejected

Thus the conclusion is

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

5 0

2 years ago

Kayla has decided to paint the ceiling in the living room. She has 1/30 gallon of paint left. The living room ceiling will take

ella [17]

So the ceiling takes 5/6 gallon to paint. We know that you already have 1/30 gallon and another gallon in addition to that. We must convert the 5/6 into ?/30 so we can see how much we need to use. So if we convert 5/6 to out of 30, we get 25/30. So the first can has 1/30 gallon so we subtract that amount from the total paint needed. So now we only need 24/30 gallon to paint the ceiling. If we subtract that amount needed from the full (30/30) can we have left, that will give us the remaining amount of paint we have left. 30/30-24/30= 6/30. This reduces to 1/5. So there is 1/5 gallon of paint left over after painting the ceiling.

3 0

2 years ago

A machine needs 2 of its gears replaced. You find 2 gears, one manufactured 5 years ago and the other manufactured 10 years ago.

Tcecarenko [31]

Probability that gear 1 will fail = 5/100 (upto 10 years)
and 8/100 (after 10 years)

Probability that both will fail = 5/100 * 8/100
= 40/10000
= 0.4 %

8 0

2 years ago

by visual inspection, determine the best-fitting regression model for the data plot below. A. No pattern B. Quadratic C.Linear D

liq [111]

Answer:

C) Linear

Step-by-step explanation:

We can see from the plot that the data approach a straight line.

This means we can draw a line of best fit through this data and it should hit several data points; thus the answer is linear.

4 0

2 years ago

Read 2 more answers

A random sample of the actual weight of 5-lb bags of mulch produces a mean of 4.963 lb and a standard deviation of 0.067 lb. If

dsp73

Answer: B) 4.963±0.019.

Step-by-step explanation:

Confidence interval for population mean ( when population standard deviation is not given) is given by :-

$\overline{x}\pm t^*\dfrac{s}{\sqrt{n}}$

, where $\overline{x}$ = Sample mean

n= Sample size

s= sample standard deviation

t* = critical t-value.

As per given:

n= 50

Degree of freedom = n-1 =49

$\overline{x}= 4.963\ lb$

s= 0.067 lb

For df = 49 and significance level of 0.05 , the critical two-tailed t-value ( from t-distribution table) is 2.010.

Now , substitute all values in the formula , we get

$4.963\pm (2.010)\dfrac{0.067}{\sqrt{50}}\\\\ 4.963\pm (2.010)(0.0094752)\\\\ 4.963\pm0.019045152\approx4.963\pm0.019$

Hence, a 95% confidence interval for the mean weight (in pounds) of the mulch produced by this company is $4.963\pm0.019$ .

Thus , the correct answer is B) 4.963±0.019.

7 0

2 years ago